In order to be accepted, a scientific theory must be

Calculate the gravitational potential energy of a 2 kg banana hanging 5

Hunter-Best [27]

Answer:

100 J

Explanation:

The potential energy is given by the formula ...

PE = mgh

= (2 kg)(10 m/s^2)(5 m) = 100 J

7 0

3 years ago

Consider the following three statements: (i) For any electro-magnetic radiation, the product of the wavelength and the frequency

Scilla [17]

Answer:

A and B

Explanation:

The relation between frequency and wavelength is shown below as:

$c=frequency\times Wavelength$

c is the speed of light having value $3\times 10^8\ m/s$

Thus, the product of the wavelength and the frequency is constant and equal to $3\times 10^8\ m/s$

Option A is correct.

Given, Frequency = $1\times 10^{18}\ Hz$

Thus, Wavelength is:

$Wavelength=\frac{c}{Frequency}$

$Wavelength=\frac{3\times 10^8}{1\times 10^{18}}\ m$

$Wavelength=3\times 10^{-10}\ m$

Also, 1 m = $3\times 10^{-10}$ Å

So,

Wavelength = 3.0 Å

Option B is correct.

As stated above, the speed of electromagnetic radiation is constant. Hence, each radiation of the spectrum travels with same speed.

Option C is incorrect.

3 0

3 years ago

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How efficient are the small and large scale solar-power systems used in individual homes and industrial settings? What is the en

Leviafan [203]

Answer:

$\color{Blue}\huge\boxed{Answer}$

The potential environmental impacts associated with solar power—land use and habitat loss, water use, and the use of hazardous materials in manufacturing—can vary greatly depending on the technology, which includes two broad categories: photovoltaic (PV) solar cells or concentrating solar thermal plants (CSP).

Explanation:

I just answer the second question

4 0

3 years ago

What are (a) the energy of a photon corresponding to wavelength 6.0 nm, (b) the kinetic energy of an electron with de Broglie wa

dlinn [17]

Explanation:

Given that,

Wavelength = 6.0 nm

de Broglie wavelength = 6.0 nm

(a). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-9}}$

$E=3.315\times10^{-17}\ J$

(b). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}$

$E=6.709\times10^{-21}\ J$

(c). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}$

$E=3.315\times10^{-11}\ J$

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}$

$E=6.709\times10^{-9}\ J$

Hence, This is the required solution.

6 0

3 years ago

Look at the advertisement. A poster that reads, "There's more to resistors than resistance. If you're really serious about cost,

ozzi

Options:

universal appeal

flattery

association

bandwagon

Answer: Association

Explanation: Advertisement is a marketing technique through which business organisations utilize the opportunities provided by both the print, electronic and other channels of communication to market a product to the target audience.

Association Advertising is a type of Advertising where certain attributes which have been known to be associated with good and quality products are used to market the products to the target audience.

7 0

3 years ago

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