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suter [353]
3 years ago
10

10. How many moles of Ne are in a 0.50L tube at 200kPa and 50 °C? 11,60​

Chemistry
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

0.04 mol Ne

General Formulas and Concepts:

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Gas Laws</u>

Combined Gas Law: PV = nRT

  • P is pressure (in kPa)
  • V is volume (in liters)
  • n is amount of moles
  • R is gas constant - \displaystyle 8.314 \frac{kPa \cdot L}{mol \cdot K}
  • T is temperature (in Kelvins)

Explanation:

<u>Step 1: Define</u>

P = 200 kPa

V = 0.50 L

T = 50°C

<u>Step 2: Identify Conversions</u>

Temperature Conversion: K = °C + 273.15

<u>Step 3: Convert</u>

  1. Substitute <em>T </em>[TC]:                      K = 50°C = 273.15
  2. Add:                                           K = 323.15

<u>Step 4: Find Moles</u>

  1. Substitute [CBL]:                    \displaystyle (200 \ kPa)(0.50 \ L) = n(8.314 \frac{kPa \cdot L}{mol \cdot K} )(323.15 \ K)
  2. Multiply:                                                                                                             \displaystyle 100 \ kPa \cdot L = n(2686.67 \frac{kPa \cdot L}{mol})
  3. Isolate <em>n</em>:                                                                                                          \displaystyle 0.037221 \ mol = n_{Ne}
  4. Rewrite:                                                                                                            \displaystyle n_{Ne} = 0.037221 \ mol

<u>Step 5: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig figs as our lowest.</em>

0.037221 mol Ne ≈ 0.04 mol Ne

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?
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Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

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In first place, the balanced reaction is:

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By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

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Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

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<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

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Then, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

Learn more about the reaction stoichiometry:

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