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Setler79 [48]
2 years ago
7

Explain why “advancing water contact angles are more sensitive to the hydrophobic property of a surface whereas receding water c

ontact angles are more sensitive to the hydrophilic property of a surface”.
Chemistry
1 answer:
timama [110]2 years ago
7 0

Answer: Surface tension has a more complicated effect on capillary pressure: on the one hand, capillary pressure is directly proportional to surface tension. High surface tension liquids, on the other hand, typically have higher contact angles, which lowers capillary pressure.

Explanation: Does this help??

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A rigid tank contains 1.40 moles of an ideal gas. Determine the number of moles of gas that must be withdrawn from the tank to l
sergey [27]

Answer : The final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

Explanation :

As we know that:

PV=nRT

At constant volume and temperature of gas, the pressure will be directly proportional to the number of moles of gas.

The relation between  pressure and number of moles of gas will be:

\frac{P_1}{P_2}=\frac{n_1}{n_2}

where,

P_1 = initial pressure of gas = 24.5 atm

P_2 = final pressure of gas = 5.30 atm

n_1 = initial number of moles of gas = 1.40 moles

n_2 = final number of moles of gas = ?

Now put all the given values in the above expression, we get:

\frac{24.5atm}{5.30atm}=\frac{1.40mol}{n_2}

n_2=0.301mol

Therefore, the final number of moles of gas that withdrawn from the tank to lower the pressure of the gas must be, 0.301 mol.

8 0
3 years ago
Identify the limiting reactant when 1.22 g of O2 reacts with 1.05 g H2 to produce water.
kupik [55]
The reaction between oxygen, O2, and hydrogen, H2, to produce water can be expressed as,

                    2H2 + O2 --> 2H2O

The masses of each of the reactants are calculated below.

          2H2 = 4(1.01 g) = 4.04 g
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Since there are 1.05 grams of O2 then, the limiting reactant is 1.22 grams of oxygen.


<em>Answer: 1.22 g of oxygen</em>
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