Answer:
Second step
(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)
Explanation:
This reaction involves;
First the ionization of the tertiary halide to firm a carbocation
Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol
First step;
(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)
Second step
(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)
This second step completes the reaction mechanism.
Answer:
Salt, (Coal is a mineral but barely, but Salt is your best answer), (And if it's multiple choice its Salt and Coal)
Explanation:
Salt (NaCl), sodium chloride, mineral substance of great importance to human and animal health, as well as to industry. The mineral form halite, or rock salt, is sometimes called common salt to distinguish it from a class of chemical compounds called salts.
Amphetamine was developed initially as a substitute for a closely-related chemical derived from the Chinese herb ma huang. That chemical is Ephedrine.
<h3>
What is Ephedrine?</h3>
Ephedrine is a stimulant medication that can be considered an amine chemical compound and substituted amphetamine.
Ephedrine is used in sports to stimulate the central nervous system (C_NS) and as energy supplier.
Ep_hedrine use is prohibited and chronic usage of this substance may have problems the health.
Learn more about Ephedrine here:
brainly.com/question/1122074
Answer:
Sugar is a polar compound , in the solid state of it Hydrogen bond strongly binds the molicules of sugar together. Being a non polar solvent and low polarity difference between Cl and C atom C—Cl bond in CCl4 is unable to form hydrogen bond. That's why sugar can't be soluble in CCl4.
Explanation:
Answer:
The molarity of the HCl solution should be 4.04 M
Explanation:
<u>Step 1:</u> Data given
volume of HCl solution = 10.00 mL = 0.01 L
volume of a 1.6 M NaOH solution = 25.24 mL = 0.02524 L
<u>Step 2:</u> The balanced equation
HCl + NaOH → NaCL + H2O
Step 3: Calculate molarity of HCl
n1*C1*V1 = n2*C2*V2
Since the mole ratio for HCl and NaOH is 1:1 we can just write:
C1*V1 =C2*V2
⇒ with C1 : the molarity of HCl = TO BE DETERMINED
⇒ with V1 = the volume og HCl = 10 mL = 0.01 L
⇒ with C2 = The molarity of NaOH = 1.6 M
⇒ with V2 = volume of NaOH = 25.24 mL = 0.02524 L
C1 * 0.01 = 1.6 * 0.02524
C1 = (1.6*0.02524)/0.01
C1 = 4.04M
The molarity of the HCl solution should be 4.04 M
