Answer:
CnH2n+2 formula
Explanation:
Alkanes have the general formula CnH2n+2, so if an alkane had 7 carbon atoms, it would have the molecular formula C7H16.
Metalloid
Explanation:
If an element is lustrous, brittle and a semi-conductor, it is best classified as a metalloid.
Metalloids shares attributes of metals and non-metals.
- They are often described as semi-metals as they do not share the full properties that makes a metal a metal.
- Metalloids are lustrous but not malleable like metals.
- They do not conduct electricity but they do so on certain conditions.
- Examples are silicon, germanium, boron, arsenic e.t.c
- They are usually found in the middle of the periodic table.
- They are not readily alloyed with metals.
Learn more:
Metalloid brainly.com/question/3023499
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<h3>Answer:</h3>
0.64 Moles of Propane
<h3>Explanation:</h3>
Data:
Moles of Carbon = 1.5 mol
Conversion factor = 7 mol C produces = 3 mol of Propane
Solution:
As we know,
7 moles of Carbon produces = 3 moles of Propane
Then,
1.5 moles of Carbon will produce = X moles of Propane
Solving for X,
X = (1.5 moles × 3 moles) ÷ 7 moles
X = 0.6428571 moles of Propane
Or rounded to two significant figures,
X = 0.64 Moles of Propane
Cao + H2O ---->Ca(OH)2
Calculate the number of each reactant and the moles of the product
that is
moles = mass/molar mass
The moles of CaO= 56.08g/ 56.08g/mol(molar mass of Cao)= 1mole
the moles of water= 36.04 g/18 g/mol= 2.002moles
The moles of Ca (OH)2=74.10g/74.093g/mol= 1mole
The mass of differences of reactant and product can be therefore
explained as
1 mole of Cao reacted completely with 1 mole H2O to produce 1 mole of Ca(OH)2. The mass of water was in excess while that of CaO was limited
