Answer:
Step-by-step explanation:
Given

and
lies between

and for this
,
and
is Positive as they lie in 2 nd Quadrant






Answer:
Step-by-step explanation:
WITHOUT replacement of first card drawn:
P(a 10 is drawn) = 13/52 = 1/4
P(the next draw is a 10) = 12/52 = 3/13
P(drawing two 10s without replacement of the first draw) = (1/4)(3/13) = 3/52
WITH replacement of first card:
P(two 10s are drawn) = P(first card is a 10)*P(first card is a 10) = (4/13)(4/13) =
16/169
C. The first is a solution, but the second is not.
5x - y/3 = 13 ; (2,-9)
substitute the letters:
5(2) - (-9/3) = 13
10 - (-3) = 13 : note that deducting a number with a negative sign turns both sign as positive.
10 + 3 = 13 ;
13 = 13
5x - y/3 = 13 ; (3,-6)
5(3) - (-6/3) = 13
15 - (-2) = 13
15 + 2 = 13
17 = 13 not equal. not a solution
hope i could help
Answer:
The new points after dilation are
(3/2, -3) and (9/2,-3)
Step-by-step explanation:
Here in this question, we want to give the new points of the line segment after it is dilated by a particular scale factor.
What is needed to be done here is to multiply the coordinates of the given line segment by the given scale factor.
Let’s call the positions on the line segment A and B.
Thus we have;
A = (1,-2) and B = (3,-2)
So by dilation, we multiply each of the specific data points by the scale factor and so we have;
A’ = (3/2, -3) and B’= (9/2,-3)
18,055
-
3,138
———-
14,927
14,927
+
18,055
———-
32,982