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grandymaker [24]
3 years ago
6

The right-hand side of the periodic table, which includes elements such as fluorine, krypton, and xenon, represents which type o

f element?
Chemistry
1 answer:
insens350 [35]3 years ago
7 0

 The  right  hand side  of the   periodic table, which include  element  such as  fluorine,Krypton  and  xenon represents    non- metals element.


 <u>Explanation</u>

  • <em>The right side  of the  periodic table consist   of non  metals.</em>
  • <em>This non metal  are elements in  group 17  which   include fluorine, chlorine,bromine  and  iodine.</em>
  • <em> It  also  comprise group 18  elements which include  neon, Argon, Radon  and Krypton.</em>

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3 years ago
Which wave has the higher frequency? <br><br> A. Bottom<br> B. Top
ladessa [460]
The top one does because there are more and it’s closer
7 0
3 years ago
The orbital period of planet Venus is 0.62 years. What is its distance from the sun?
Vikki [24]

Kepler's third law shows the relationship between the orbital period of an object and the distance between the object and the object it orbits.

The simplified version of this law is: P^2 = a^3

Where,

P = period of the orbit in years = 0.62 years

a = average distance from the object to the object it orbits in AU. The astronomical unit AU is a unit of length which is roughly equivalent to the distance from Earth to the Sun.

Therefore calculating for a:

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5 0
3 years ago
1.72 moles of NOCI were placed in a 2.50 L reaction chamber
elena-14-01-66 [18.8K]

The equilibrium constant, Kc=0.026

<h3>Further explanation</h3>

Given

1.72 moles of NOCI

1.16 moles of NOCI  remained

2.50 L reaction chamber

Reaction

2NOCI(g) = 2NO(g) + Cl2(g).

Required

the equilibrium constant, Kc

Solution

ICE method

   2NOCI(g) = 2NO(g) + Cl2(g).

I    1.72

C   0.56           0.56         0.28

E   1.16              0.56         0.28

Molarity at equilibrium :

NOCl :

\tt \dfrac{1.16}{2.5}=0.464

NO :

\tt \dfrac{0.56}{2.5}=0.224

Cl2 :

\tt \dfrac{0.28}{2.5}=0.112

\tt Kc=\dfrac{[NO]^2[Cl_2]}{[NOCl]^2}\\\\Kc=\dfrac{0.224^2\times 0.112}{0.464^2}=0.026

4 0
3 years ago
What is the concentration of the murexide soution with a transmittance of 28.65%. (molar absorptivity = 3847)
Ainat [17]

Answer:

The concentration of the murexide solution is 0.0000745 M

Explanation:

From Beer-Lambert's law,

A = εlc

A = Absorbance = 28.65% = 0.2865

ε = molar absorptivity = 3847 M/cm

l = path length = 1cm

c = concentration in mol/L = ?

c = A/εl = 0.2865/(3847×1) = 0.0000745 mol/L

Hope this Helps!

6 0
2 years ago
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