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kupik [55]
3 years ago
13

For the cells in a human body, an isotonic solution is 0.9% NaCl. If a red blood cell is placed in a 1% NaCl solution, what will

happen to the cell?
Chemistry
1 answer:
igomit [66]3 years ago
6 0

Answer: The red blood cell will shrink due to water loss

Explanation:

Because 1% NaCl solution is slightly more concentrated than its isotonic 0.9% form, the red blood cell will lose its cell containing fluids such as water to the MORE concentrated environment.

This water loss after a prolonged period will result in shrinking of the red blood cell.

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The second equation is balanced

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This is because the number of elements of each atom in the product side equal the number of elements of each atom on the reactant side.

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