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kupik [55]
3 years ago
13

For the cells in a human body, an isotonic solution is 0.9% NaCl. If a red blood cell is placed in a 1% NaCl solution, what will

happen to the cell?
Chemistry
1 answer:
igomit [66]3 years ago
6 0

Answer: The red blood cell will shrink due to water loss

Explanation:

Because 1% NaCl solution is slightly more concentrated than its isotonic 0.9% form, the red blood cell will lose its cell containing fluids such as water to the MORE concentrated environment.

This water loss after a prolonged period will result in shrinking of the red blood cell.

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Determine the empirical formula for C6H3Br3.
Mazyrski [523]

Answer:

C2HBr

Explanation:

The empirical formula is like the simpliest form so divide all by 3 and get the above formula.

3 0
2 years ago
Why do we use the mole concept ??
Kaylis [27]

Answer:

Here

Explanation:

Chemists need the mole concept to bridge the gap between the microscopic world of atoms to the macroscopic world of humans. As you know, the molecular level consists of particles that are invisible to us.

7 0
3 years ago
Read 2 more answers
The half life for the first order conversion of A to B is 56.6 hours. How long does it take for the concentration of A to decrea
sveta [45]

Answer:

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

Explanation:

A → B

Initial concentration of the reactant = x

Final concentration of reactant = 10% of x = 0.1 x

Time taken by the sample, t = ?

Formula used :

A=A_o\times e^{-\lambda t}\\\\\lambda =\frac{0.693}{t_{\frac{1}{2}}}

where,

A_o = initial concentration of reactant

A = concentration of reactant left after the time, (t)

t_{\frac{1}{2}} = half life of the first order conversion  = 56.6 hour

\lambda = rate constant

A=A_o\times e^{-(\frac{0.693}{t_{1/2}})\times t}

Now put all the given values in this formula, we get

0.1x=x\times e^{-(\frac{0.693}{56.6 hour})\times t}

t = 188.06 hour

It will take 188.06 hours for the concentration of A to decrease 10.0% of its original concentration.

4 0
3 years ago
What is the solubility in moles/liter for silver chloride at 25 oC given a Ksp value of 1.6 x 10-10. Write using scientific nota
trapecia [35]

Answer:

Explanation:

AgCl      ⇄       Ag⁺       +       Cl⁻

m                       m                   m

If x mole of AgCl be dissolved in one litre .

[ Ag⁺ ] [ Cl⁻ ] = 1.6 x 10⁻¹⁰

m² =  1.6 x 10⁻¹⁰

m = 1.26 x 10⁻⁵ moles

So solubility of AgCl is 1.26 x 10⁻⁵ moles / L

5 0
3 years ago
Howtocalculatethevolumeofcarbondioxideproducedwhen400gofmarblewereats.t.p<br>​
lys-0071 [83]

Answer:

so 0.15 moles X 22.4 dm3/mole=3.36 dm3. Next we find the moles of hexane combusted, and then the moles of CO2. Finally, we find the volume of CO2 using the fact that at STP, 1 mole of gas = 22.4 dm3.

3 0
3 years ago
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