Question

Please help me solve this!!

Answer 1

Answer:

Abelito had the greater average speed

Step-by-step explanation:

Given

Bobby:

$Distance =4\ miles$

$Time = 30\ minutes$

Abelito

$Distance = 10\ miles$

$Time = 48\ minutes$

Required:

Who had a greater average speed

Average speed (S) is calculated as:

$S = \frac{Distance}{Time}$

We will make use of mph (miles per hour) as the unit of speed.

For Bobby:

$S_B = \frac{4\ miles}{30\ minutes}$

Convert minute to hour

$S_B = \frac{4\ miles}{0.5\ hr}$

$S_B = 8mph$

For Abelito

$S_A = \frac{10\ miles}{48\ minutes}$

Convert minute to hour

$S_A = \frac{10\ miles}{0.8\ hr}$

$S_A = 12.5mph$

By comparison: 12.5mph > 8mph

Hence: Abelito had the greater average speed