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cricket20 [7]
3 years ago
9

Can someone please help me with this.

Mathematics
1 answer:
Doss [256]3 years ago
6 0
F(a)= -3a+2b

Hope this helps!
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Help me solve for x and y .
Olegator [25]

Answer:

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
How to wirte a linear equation from a graph
astra-53 [7]
Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!
8 0
4 years ago
In triangle ABC, line A.B.=CB Angle ABC equals 4X -3, and angle CAB equals X -3, what is angle ACB
Soloha48 [4]

Answer:

∠ACB = 28.5

Step-by-step explanation:

In triangle ABC,

angle CAB = x-3

angle ABC = 4X-3

It is also given that AB=CB

We know that if two sides of any triangle are equal then corresponding sides must also be equal.

Hence

angle ACB = angle CAB

angle ACB = x-3    {Given that angle CAB = x-3 }

We know that sum of all three angles of a triangle is 180 degree so let's add given angles

angle ACB + angle CAB + angle ABC = 180

(x-3) + (x-3) + (4x-3) = 180

x-3 + x-3 + 4x-3 = 180

6x-9 = 180

6x = 180+9

6x = 189

x = 189/9

x= 31.5

Now plug value of x into

angle ACB = x-3 = 31.5-3 = 28.5

Hence final answer is

∠ACB = 28.5


3 0
3 years ago
7. Find an equation of the line containing (- 4,5) and perpendicular to the line 5x - 3y = 4.
bagirrra123 [75]

The equation of the line containing (- 4,5) and perpendicular to the line 5x - 3y = 4 is y = -3 / 5 x + 13 / 5

<h3>How to find the equation of a line?</h3>

The equation of a line can be represented as follows:

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore, the equation passes through (-4, 5) and perpendicular to 5x - 3y = 4

Hence,

perpendicular lines follows the rule below:

m₁m₂ = -1

Hence,

5x - 3y = 4

5x - 4 = 3y

y = 5/ 3 x - 4 / 3

m₁ = 5 / 3

5/3 m₂ = -1

m₂ = - 3 / 5

Hence,

using (-4, 5)

5 = - 3 / 5 (-4) + b

5 = 12 / 5 + b

b = 5 - 12 / 5 = 25 - 12 /5 = 13 / 5

Therefore,

y = -3 / 5 x + 13 / 5

learn more on equation of a line here: brainly.com/question/10727767

#SPJ1

6 0
2 years ago
Read 2 more answers
Rewrite the expressions in each pair so that they have the same base. c) (1 /2)^2x and (1/ 4)^x - 1
just olya [345]
I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
7 0
3 years ago
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