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forsale [732]
3 years ago
14

How can we measure an endothermic and exothermic reaction?

Chemistry
1 answer:
Butoxors [25]3 years ago
7 0
The answer is temperature!
You might be interested in
PV = nRT. If P = 1 atm, V = 5.0 liter, R = 0.0821 L.atm/mol.K, and T = 293 K; what is the value of n?
Leya [2.2K]

Answer:

n = 0.207 mole

Explanation:

We have,

P = 1 atm

V = 5 liter

R = 0.0821 L.atm/mol.K

T = 293 K

We need to find the value of n. The relation is as follows :

PV = nRT

Solving for n,

n=\dfrac{PV}{RT}\\\\n=\dfrac{1\times 5}{0.0821 \times 293}\\\\n=0.207\ \text{mol}

So, the value of n is 0.207 mol.

6 0
3 years ago
Consider the following balanced equation for the following reaction:
Sidana [21]

<u>Answer:</u> The actual yield of the carbon dioxide is 47.48 grams

<u>Explanation:</u>

For the given balanced equation:

15O_2(g)+2C_6H_5COOH(aq.)\rightarrow 14CO_2(g)+6H_2O(l)

To calculate the mass for given number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Theoretical moles of carbon dioxide = 1.30 moles

Molar mass of carbon dioxide = 44 g/mol

Putting values in above equation, we get:

1.30mol=\frac{\text{Theoretical yield of carbon dioxide}}{44g/mol}\\\\\text{Theoretical yield of carbon dioxide}=(1.30mol\times 44g/mol)=57.2g

To calculate the theoretical yield of carbon dioxide, we use the equation:

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100

Theoretical yield of carbon dioxide = 57.2 g

Percentage yield of carbon dioxide = 83.0 %

Putting values in above equation, we get:

83=\frac{\text{Actual yield of carbon dioxide}}{57.2}\times 100\\\\\text{Actual yield of carbon dioxide}=\frac{57.2\times 83}{100}=47.48g

Hence, the actual yield of the carbon dioxide is 47.48 grams

7 0
3 years ago
What is the oxidation state of S in so ??​
Marina86 [1]

Answer:

+2

Explanation:

If a compound SO existed, we would identify the oxidation state of sulfur using the following logic:

  • oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
  • oxygen typically has an oxidation state of -2;
  • we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
  • if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
  • write the equation for the net charge of 0 by adding all individual charges of the two atoms: x + (-2) = 0;
  • hence, x = 2.

That said, in this hypothetical compound S would have an oxidation state of +2.

6 0
3 years ago
Which color in the rainbow has the longest wavelength? 1. orange 2. blue3. yellow4.green 5. red
rodikova [14]

In rainbow, the color that has the longest wavelength is red which means option 5 is the correct choice.

Dispersion is described to be the spreading of white mild into its complete spectrum of colors, in truth we also can say a complete spectrum of wavelengths. The white mild turns into from solar and includes seven colors. On one end of the spectrum is red with the longest wavelength. Blue or violet mild has the shortest wavelength. White mild is a aggregate of all hues withinside the color spectrum. The colors of the rainbow are: Red, orange, yellow, green, blue, indigo, violet.

Therefore, option 5 is the correct choice.

To learn more about rainbow check the link below:

brainly.com/question/12008276

#SPJ4

6 0
1 year ago
Which element or compound has lost electrons in this oxidation-reduction reaction? 4li 2coo → 2co 2li2o a. coo b. li2o c. li d
Nady [450]

Answer:

       Correct option is C.

Explanation:

Such type of chemical reaction that involves a transfer of electrons between two species is known as oxidation-reduction or redox reaction.

Redox reaction is oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.

For this reaction:

           On reactant side:

Oxidation state of oxygen, cobalt, lithium = -2 ,+2, 0

While on product side of reaction:

Oxidation state of cobalt, oxygen, lithium = 0, -2, +1

Here, oxidation reaction take place because oxidation state of lithium is increased. While the oxidation state of cobalt in reducing, it is gaining electrons and so it undergoes reduction reaction.

So, Option C (Li) is correct.

Learn more about oxidation-reduction reaction:

brainly.com/question/13293425

#SPJ4

7 0
2 years ago
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