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alexdok [17]
3 years ago
9

Balance the equation of. _C + _O2 -- _CO

Chemistry
1 answer:
scoundrel [369]3 years ago
8 0

Explanation:

2C +O2 = 2CO

this will be the answer

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1375 J of heat energy are added to a 50.0 g sample of copper, which increases temperature from 22.8 C to 94.2 C. Calculate the s
sergeinik [125]

Answer:

0.385 J/g°C

Explanation:

Using the following formula, the specific heat of an elemental substance can be calculated:

Q = m × c × ∆T

Where;

Q = quantity of heat (J)

m = mass (g)

c = specific heat capacity (J/g°C)

∆T = change in temperature (°C)

Based on the given information, Q = 1375J, m = 50g, initial temperature = 22.8°C, final temperature = 94.2°C, c =?

Q = m × c × ∆T

1375 = 50 × c × (94.2 - 22.8°C)

1375 = 50 × c × 71.4

1375 = 3570c

c = 1375/3570

c = 0.3851

c = 0.385 J/g°C

3 0
3 years ago
Given the following two quantities: 0.50 mol of CH4 and 1.0 mol of HCl,
Vinil7 [7]

Answer:

(a) HCl

(b) HCl

(c) HCl

(d) HCl

Explanation:

<em>Given: </em>0.50 mol of CH₄ and 1.0 mol of HCl

Using stoichiometry we can calculate the answers to parts a, b, c, and d.

<h3>Part (a) </h3>

# of moles × Avogadro's number = # of atoms or molecules

Avogadro's number: 6.02 * 10²³

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms CH}_4}{1 \ \text{mol CH}_4} = 3.01 \cdot 10^2^3 \ \text{atoms CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{6.02\cdot 10^2^3 \ \text{atoms HCl}}{1 \ \text{mol HCl}} = 6.02 \cdot 10^2^3 \ \text{atoms HCl}

HCl has more atoms than CH₄.

<h3>Part (b) </h3>

This is calculated the same way as Part (a); HCl has more molecules than CH₄.

<h3>Part (c) </h3>

Molar mass of CH₄ = 16.04 g/mol

Molar mass of HCl = 36.458 g/mol

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{16.04 \ \text{g CH}_4}{1 \ \text{mol CH}_4} = 8.02 \ \text{g CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{36.458 \ \text{g HCl}}{1 \ \text{mol HCl}} = 36.458 \ \text{g HCl}

HCl has a greater mass than CH₄.

<h3>Part (d)</h3>

Assuming STP:

Molar volume of any gas at STP is 22.4 L/mol.

  • \displaystyle 0.50\ \text{mol CH}_4 \cdot \frac{22.4 \ \text{L CH}_4}{1 \ \text{mol CH}_4} = 11.2 \ \text{L CH}_4
  • \displaystyle 1.0\ \text{mol HCl} \cdot \frac{22.4 \ \text{L HCl}}{1 \ \text{mol HCl}} = 22.4 \ \text{L HCl}

HCl has a greater volume than CH₄.

5 0
3 years ago
What would scientist do to best communicate these data to other scientists in a presentation
frosja888 [35]

Most likely use scientific names and list the procedures taken

4 0
3 years ago
Read 2 more answers
What is the % by mass of oxygen in Mg(NO3)2 ?
Mashcka [7]

Answer:

72.71 %

Explanation:

For oxygen: mass % O = (mass of 1 mol of oxygen/mass of 1 mol of CO2) x 100. mass % O = (32.00 g / 44.01 g) x 100. mass % O = 72.71 %

HOPED THIS HELPED YOU OUT

A brainliest is always appreciated.

5 0
2 years ago
1. What does it mean for a substance to be soluble?​
Anni [7]

Answer:

Solubility is a chemical property referring to the ability for a given substance, the solute, to dissolve in a solvent. It is measured in terms of the maximum amount of solute dissolved in a solvent at equilibrium. ... Certain substances are soluble in all proportions with a given solvent, such as ethanol in water.

Explanation:

3 0
4 years ago
Read 2 more answers
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