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lesya [120]
3 years ago
8

5. (Hint: Treat this package falling as a horizontal projectile) A pilot of a

Physics
1 answer:
Firlakuza [10]3 years ago
4 0

Question: Where is the question to this question? Please be more specific.

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Which statement best describes the movement of electrical current when a capacitor is used in a circuit?
Masteriza [31]

Answer: B.

Capacitors prevent current from moving through a circuit 

Explanation:

If a direct voltage is applied on the capacitor, no conduction current flows through the capacitor if its insulating medium is perfect insulator. This is due to the fact that there are no free charge carriers in such medium. Basically the real insulator contains very few charge carriers and therefore a very small leakage current passes in the capacitor depending on the conductivity of the insulator.

If an alternating voltage is applied on the capacitor, a displacement current passes through the capacitor irrespective of the insulating medium. This current is termed also the capacitive current. It flows because of changing electric displacement with time.

4 0
3 years ago
What causes objects to move or stay still (support your details with claims and evidence)
maxonik [38]
Force moves the object but if the same anyone force is applied to both sides then it doesn’t move
6 0
3 years ago
Radar uses radio waves of a wavelength of 2.9 m . The time interval for one radiation pulse is 100 times larger than the time of
Mandarinka [93]

Answer:

145 m

Explanation:

Given:

Wavelength (λ) = 2.9 m  

we know,

c = f × λ  

where,

c = speed of light ; 3.0 x 10⁸ m/s

f = frequency  

thus,

f=\frac{c}{\lambda}

substituting the values in the equation we get,

f=\frac{3.0\times 10^8 m/s}{2.9m}

f = 1.03 x 10⁸Hz  

Now,

The time period (T) = \frac{1}{f}

or

T =  \frac{1}{1.03\times 10^8}  = 9.6 x 10⁻⁹ seconds  

thus,

the time interval of one pulse = 100T = 9.6 x 10⁻⁷ s  

Time between pulses = (100T×10) = 9.6 x 10⁻⁶ s  

Now,

For radar to detect the object the pulse must hit the object and come back to the detector.

Hence, the shortest distance will be half the distance travelled by the pulse back and forth.

Distance = speed × time = 3 x 10^8 m/s × 9.6 x 10⁻⁷ s) = 290 m {Back and forth}  

Thus, the minimum distance to target = \frac{290}{2} = 145 m

6 0
3 years ago
Divers in Acapulco dive from a cliff that is 65 m high. If the rocks
Ghella [55]

Answer:

did you have the same answer to get the best

6 0
3 years ago
A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show
Marizza181 [45]

Answer:

Explanation:

v^2-u^2=2as\\40^2-10^2=2a*125\\1600-100=250a\\a=\frac{1500}{250}=6~m/s^2\\v=u+at\\40=10+6t\\6t=30\\ t=\frac{30}{6}=5 ~s

7 0
3 years ago
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