A uniformly charged rod (length = 2.0 m, charge per unit length = 3.0 nC/m) is bent to form a semicircle. What is the magnitude
of the electric field at the center of the circle? Select one: O a. 64N/C b. 85N/C c. 34N/C 3 d. 133Njc -j e.48N/C
1 answer:
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Answer:
The gravitational pull is determined by the mass and distance.
Explanation:
According to Newton's law of universal gravitation
where F is the gravitational pull, G is gravitational constant, m₁ and m₂ are masses of bodies and r is the distance between them.
It can be seen from the above equation that F is directly proportional to the product of the masses and inversely proportional to the square of distance between them.
F ∝ m₁m₂
F ∝ 1/r²
Answer:
The length is and the angle is
Explanation:
The period of the pendulum is related to its length
by
where is the acceleration due to gravity.
Solving for we get
putting in and
we get:
There are two forces acting on the pendulum: The gravitational force and the
student's force. Therefore, the angular displacement
that these forces give is
putting in ,
, and
we get