______ is the type of heat that roasts the marshmallows.

When equal moles of an acid and a base are mixed, after reaction the two are compounds are said to be at the _______________. Se

Elodia [21]

Answer:

when equal moles of an acid and base are mixed,after reaction the two are compounds are said to be at the Equivalent point.

3 0

3 years ago

What volume would 56.2 mL of gas at 820 mm of Hg occupy at 720 mm of Hg?

Andreyy89

Answer:

49.35 mL

Explanation:

Given: 56.2 mL of gas

To find: volume that 56.2 mL of gas at 820 mm of Hg would occupy at 720 mm of Hg

Solution:

At 820 mm of Hg, volume of gas is 56.2 mL

At 1 mm of Hg, volume of gas is $\frac{56.2}{820}$

At 720 mm of Hg, volume of gas is $\frac{56.2}{820}(720)=49.35\,\,mL$

3 0

3 years ago

Does Monocercomonoides still meet the definition of a eukaryote? Why or why not?

KengaRu [80]

Answer:

Yes

Explanation:

They are a unique type of eukaryote because they lack an important organelle: mitochondria. Mitochondria are essential for producing cellular energy in most eukaryotic cells. However, due to its habitat, it is able to acquire energy from a process called sulfur mobilization.

They are significant because they challenge the idea that eukaryotes need mitochondria to be classified as eukaryotic. However, they have other membrane-bound organelles such as a nucleus and Golgi apparatus, meaning they remain eukaryotic.

Research suggest they lost their mitochondria over time, rather than never having had them throughout their ancestry.

Because of all these reasons, they still meet the definition of a eukaryote.

6 0

3 years ago

Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the co

Lilit [14]

Answer:

0.0119

Explanation:

There was a part missing. I think this is the whole question:

<em>Before any reaction occurs, the concentration of A in the reaction below is 0.0510 M. What is the equilibrium constant if the concentration of A at equilibrium is 0.0153 M?</em>

A (aq) ⇌ 2B (aq) + C(aq)

<em>Remember to use correct significant figures in your answer. Do not include units in your response.</em>

First, we have to make an ICE Chart, which stands for initial, change and equilibrium. We will call "x" unknown concentrations.

A (aq) ⇌ 2B (aq) + C (aq)

I 0.0510 0 0

C -x +2x +x

E 0.0510-x 2x x

Since the concentration at equilibrium of A is 0.0153 M, we get

$0.0510 - x = 0.0153 \\x = 0.0357$

We can use the value of x to calculate the concentrations at equilibrium.

$[A]e = 0.0153 M \\[B]e = 2x = 2(0.0357) = 0.0714 M \\[C]e = x = 0.0357 M \\$

The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.

$Kc = \frac{[B]^{2} \times [C]}{[A]} = \frac{0.0714^{2} \times 0.0357}{0.0153} = 0.0119$

The equilibrium constant for this reaction at equilibrium is 0.0119.

You can learn more about equilibrium here: brainly.com/question/4289021

7 0

2 years ago

Read 2 more answers

What role could energy have played in forming the black sand on the beach?

Ivan

The role energy would have played in forming the black sand on the beach

will be through the erosion and movement of the particles.

Black sand from the beach are formed as a result of the erosion of volcanic

material , dark-colored rocks and minerals. Erosion helps to carry these

particles to the beach thereby making the color of the sand to become dark.

The wave energy present at the beach erodes and moves the materials to

different parts of the beach.

Read more on brainly.com/question/17905503

6 0

2 years ago