Answer:
9.52g of N2
Explanation:
The equation of the reaction is given as;
2NO(g) + 2H2(g) → N2(g) + 2H2O(l)
From the stochiometry of the reaction;
2 mol : 2 mol : 1 mol : 2 mol
60g : 4g : 28g :
(
Mass = Number of moles * Molar mass)
Converting the masses given to moles;
Number of moles of NO = mass / molar mass = 20.4 / 30 = 0.68
Number of moles of H2 = mass / molar mass = 5.10 / 2 = 2.55
In this reaction, the limiting reactant is NO
60g of NO produces 28g of N2,
20.4g of NO would produce xg of N2
60 = 28
20.4 = X
X = (20.4 * 28) / 60
X = 9.52g
