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2 years ago

2. Pick two materials that float from the table above.

Chemistry

1 answer:

8090 [49]2 years ago

7 0

Explanation:

so let's say fertilizer sinks it would be higher density and like salt it would be a solvent hope that helps honestly it probably did not but kind of a guide I guess and another one is ice it will be like a toy and here's a tip water is and always will be 1 gl

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Name the difference(s) between an plant and animal cell? Question 1 options: a animal cells do not contain chloroplasts b animal

Bogdan [553]

answer should be d :)

7 0

3 years ago

:( plz help and can u guys help me with my math

astra-53 [7]

Answer:

Explanation:

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<h2> ~jimmarion~</h2>

3 0

3 years ago

Read 2 more answers

Read the chemical equation.

Sladkaya [172]

Answer:- D. 1.8 moles of Fe and $2.7molCO_2$ .

Solution:- The balanced equation is:

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

let's first figure out the limiting reactant using the given moles and mol ratio:

$1.8molFe_2O_3(\frac{3molCO}{1molFe_2O_3})$

= 5.4 mol CO

From calculations, 5.4 moles of CO are required to react completely with 1.8 moles of Iron(III)oxide but only 2.7 moles of CO are available. It means CO is limiting reactant.

Products moles depends on limiting reactant. Let's calculate the moles of each reactant formed for given 2.7 moles of CO.

$2.7molCO(\frac{2molFe}{3molCO})$

= 1.8 mol Fe

$2.7molCO(\frac{3molCO_2}{3molCO})$

= $2.7molCO_2$

So, the correct choice is D. 1.8 moles of Fe and $2.7molCO_2$ are formed.

6 0

3 years ago

You can obtain a rough estimate of the size of a molecule with the following simple experiment: Let a droplet of oil spread out

mina [271]

Answer:

The diameter of the oil molecule is $4.4674\times 10^{-8} cm$ .

Explanation:

Mass of the oil drop = $m=9.00\times 10^{-7} kg$

Density of the oil drop = $d=918 kg/m^3$

Volume of the oil drop: v

$d=\frac{m}{v}$

$v=\frac{m}{d}=\frac{9.00\times 10^{-7} kg}{918 kg/m^3}$

Thickness of the oil drop is 1 molecule thick.So, let the thickness of the drop or diameter of the molecule be x.

Radius of the oil drop on the water surface,r = 41.8 cm = 0.418 m

1 cm = 0.01 m

Surface of the sphere is given as: a = $4\pi r^2$

$a=4\times 3.14\times (0.418 m)^2=2.1945 m^2$

Volume of the oil drop = v = Area × thickness

$\frac{9.00\times 10^{-7} kg}{918 kg/m^3}=2.1945 m^2\times x$

$x= 4.4674\times 10^{-10} m= 4.4674\times 10^{-8} cm$

The thickness of the oil drop is $4.4674\times 10^{-8} cm$ and so is the diameter of the molecule.

6 0

2 years ago

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J.

timofeeve [1]

Complete question:

ΔU for a van der Waals gas increases by 475 J in an expansion process, and the magnitude of w is 93.0 J. calculate the magnitude of q for the process.

Answer:

The magnitude of q for the process 568 J.

Explanation:

Given;

change in internal energy of the gas, ΔU = 475 J

work done by the gas, w = 93 J

heat added to the system, = q

During gas expansion process, heat is added to the gas.

Apply the first law of thermodynamic to determine the magnitude of heat added to the gas.

ΔU = q - w

q = ΔU + w

q = 475 J + 93 J

q = 568 J

Therefore, the magnitude of q for the process 568 J.

6 0

3 years ago