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3 years ago

6

I need help really bad

1 answer:

Stella [2.4K]3 years ago

5 0

The answer is 18. You add 5 to both sides of the equation. the 5 cancels out. You are left with 2/3x=12. Then you divide 12 by 2/3 to get x. 12 divided by 2/3 is 18

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Help me pls imma fail

KatRina [158]

Answer:

-

Step-by-step explanation:

3 0

2 years ago

What is the Value of x+y ? PLZ Help ASAP

Natalija [7]

ANSWER

$x + y = 60$

EXPLANATION

Method 1

Vertically opposite angles are equal, therefore

$3x + 55 = 85$

This implies that,

$3x = 85 - 55$

We simplify to get,

$3x = 30$

Dividing through by 3 gives,

$x = 10$

Also,

$2y - 5 = 95$

This implies that,

$2x = 95 + 5$

We simplify the right hand side to get,

$2x = 100$

We divide both sides both sides by 2 to get,

$x = 50$

$x + y = 50 + 10$

$x + y = 60$

Method 2

Angles on straight line sums to 180°.

$2y-5+85=180$

This implies that,

$2y+80=180$

$2y=180-80$

$2y=100$

$y=50$

Also,

$3x+55+95=180$

$3x+150=180$

$3x=180-150$

$3x=30$

$x=10$

$x+y=50+10$

$x+y=60$

7 0

3 years ago

Read 2 more answers

31. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Whitepunk [10]

Answer:

The required linear equation satisfying the given conditions f(-1)=4 and f(5)=1 is $y=\frac{-1}{2} x+\frac{7}{2}$

Step-by-step explanation:

It is given that f(-1)=4 and f(5)=1.

It is required to find out a linear equation satisfying the conditions f(-1)=4

and f(5)=1. linear equation of the line in the form

$\left(y-y_{2}\right)=m\left(x-x_{2}\right)$

Step 1 of 4

Observe, f(-1)=4 gives the point (-1,4)

And f(5)=1 gives the point (5,1).

This means that the function f(x) satisfies the points (-1,4) and (5,1).

Step 2 of 4

Now find out the slope of a line passing through the points (-1,4) and (5,1),

$\begin{aligned}&m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} \\&m=\frac{1-4}{5-(-1)} \\&m=\frac{-3}{5+1} \\&m=\frac{-3}{6} \\&m=\frac{-1}{2}\end{aligned}$

Step 3 of 4

Now use the slope $m=\frac{-1}{2}$ and use one of the two given points and write the equation in point-slope form:

$(y-1)=\frac{-1}{2}(x-5)$

Distribute $\frac{-1}{2}$ ,

$y-1=\frac{-1}{2} x+\frac{5}{2}$

Step 4 of 4

This linear function can be written in the slope-intercept form by adding 1 on both sides,

$\begin{aligned}&y-1+1=\frac{-1}{2} x+\frac{5}{2}+1 \\&y=\frac{-1}{2} x+\frac{5}{2}+\frac{2}{2} \\&y=\frac{-1}{2} x+\frac{7}{2}\end{aligned}$

So, this is the required linear equation.

8 0

2 years ago

Please help will give points!!!!

slavikrds [6]

Answer:

Between 1 and 6

3 0

4 years ago

Make s the subject of the formula t²=2p+as

Romashka-Z-Leto [24]

Answer:

${t}^{2} = 2p + as \\ {t}^{2} - 2p = as \\ divide \: both \: sides \: by \: a \\ s = \frac{ {t}^{2} - 2p }{a}$

8 0

3 years ago