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Likurg_2 [28]
3 years ago
15

Write the point-slope form of the equation of the line that passes through the points (6.-9) and (7.1). Include your work in

Mathematics
1 answer:
Charra [1.4K]3 years ago
8 0

Answer:

Y-1 = 10(X-7)

Step-by-step explanation:

Y -Y1 = M(X - X1)

Y1= 1

X1= 7

M= SLOPE

SLOPE= -9-1 DIVIDED BY 6-7.

-10 DIVIDED BY -1 EQUALS 10

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Answer quick please.
Brilliant_brown [7]

Answer

The Answer is A C D

Step-by-step explanation:

4 0
2 years ago
A car traveled 88 km in 1 hour, 90 km in the next 2 hours, and then 76 km in 1 hour before reaching its destination. what was th
luda_lava [24]

The formula for Average speed = \frac{Total Distance}{Total Time}

The car travels 80 km in 1 hour.

Then the car travels 90 km in 2 hours.

And finally the car travels 76 km in 1 hour

So the total distance covered by the car = 80 + 90 + 76 = 246 km

The total time taken to cover this distance = 1 + 2 + 1 = 4 hours.

So average speed = \frac{246}{4}= 61.5

The average speed of the car is 61.5 km / h

3 0
3 years ago
Given the following functions f(x) and g(x), solve (f ⋅ g)(3) and select the correct answer below:
Ksenya-84 [330]
I believe you may have the order incorrect. If we were looking at g(f(x)) the answer would be 47. We would get this by sticking the 3 in for x in f(x) and solving, which would give us 48. We would then stick that answer in for x in the g(x), giving us 47. 

In its current order the answer would be 28. 
6 0
3 years ago
I NEED HELP ASAP!!!!!!!!!!!!!!!
bagirrra123 [75]

Answer:

\tan(j)  =  \frac{35}{12}  = 2 \times \frac{9}{12}

Step-by-step explanation:

remember: tan(theta) = opposite/adjacent

3 0
3 years ago
The probability that a student pilot passes the written test for a private pilot's license is 0.7. what is the probability that
zhenek [66]
<span>Probability = 0.063 Fourth try = 0.0973 Let X be the number of failed attempts at passing the test before the student passes. This is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7 and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p) xp. The probability P that the student passes on the third try means that there were x = 2 failed attempts or P = nb(2, ; 1, .7) = (.3)2 (.7) = 0.063 . The probability that the student passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤ 2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0 (.7) + (.3)1 (.7) + (.3)2 (.7) = 0.973 .</span>
4 0
3 years ago
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