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Irina-Kira [14]
3 years ago
10

Where is the function increasing? A) 1 < x < ∞ B) 3 < x < ∞ C) -∞ < x < 1 D) -∞ < x < 3

Mathematics
1 answer:
Vlad1618 [11]3 years ago
4 0

Answer: I think its A

Step-by-step explanation:

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A woman bought some large frames for $16 each and some small frames for $7 each at a closeout sale. If she bought 24 frames for
8090 [49]

Answer:

20 big 4 small

Step-by-step explanation:

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3 years ago
Marla did 65 set ups each day for a week use the distributive property to show an expression you can use to find the total numbe
Maslowich
<span>X = 65(7) 
X = 455
Marla did 455 sit-ups in a week</span>
5 0
3 years ago
Find the max and min values of f(x,y,z)=x+y-z on the sphere x^2+y^2+z^2=81
Anton [14]
Using Lagrange multipliers, we have the Lagrangian

L(x,y,z,\lambda)=x+y-z+\lambda(x^2+y^2+z^2-81)

with partial derivatives (set equal to 0)

L_x=1+2\lambda x=0\implies x=-\dfrac1{2\lambda}
L_y=1+2\lambda y=0\implies y=-\dfrac1{2\lambda}
L_z=-1+2\lambda z=0\implies z=\dfrac1{2\lambda}
L_\lambda=x^2+y^2+z^2-81=0\implies x^2+y^2+z^2=81

Substituting the first three equations into the fourth allows us to solve for \lambda:

x^2+y^2+z^2=\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}+\dfrac1{4\lambda^2}=81\implies\lambda=\pm\dfrac1{6\sqrt3}

For each possible value of \lambda, we get two corresponding critical points at (\mp3\sqrt3,\mp3\sqrt3,\pm3\sqrt3).

At these points, respectively, we get a maximum value of f(3\sqrt3,3\sqrt3,-3\sqrt3)=9\sqrt3 and a minimum value of f(-3\sqrt3,-3\sqrt3,3\sqrt3)=-9\sqrt3.
5 0
3 years ago
??? Anyone know how to answer this question
True [87]
Answer: 35 additional teachers are needed

-------------------------------------------------
-------------------------------------------------

Explanation:

We have 2470 students and the ratio of students to teachers is 26:1. This means that for every teacher, there are 26 students. Put another way, we can set up this ratio

2470/x = 26/1

where x is the number of teachers. Cross multiply and solve for x

2470/x = 26/1
2470*1 = 26*x
2470 = 26x
26x = 2470
26x/26 = 2470/26
x = 95

So we have 95 teachers currently

-------------

Let y be the new number of teachers needed to bring the ratio down to 19:1

Using a similar idea as done above, we would have this ratio

2470/y = 19/1

Let's solve for y
2470/y = 19/1
2470*1 = 19*y
2470 = 19y
19y = 2470
19y/19 = 2470/19
y = 130

So we'll need 130 teachers to have the ratio be 19:1

The difference of the values is y - x = 130 - 95 = 35, which is the final answer. This is the additional amount of teachers needed.
5 0
3 years ago
90% on a test. If he answered 135 questions correctly, how many questions were on the test?
USPshnik [31]

Answer:

150

Step-by-step explanation:

3 0
3 years ago
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