<span>The problem is basically asking you to approximate the square root of numbers that are not perfect squares. You should be able to recognize that 54 is very close to 49 and you should know that the square root of 49 is 7. You should also know that the next perfect square is 64 (whose square root is 8). Therefore the square root of 50 is between 7 and 8, but closer to 7 since 50 is closer to 49.</span>
A) The equation for circumference is C=2piR. So Filling in for circle A we have 28.26=2*pi*4.5 so we want to isolate pi which I'm gonna call x for it's easier for me xD. So we're gonna start by dividing 4.5 from each side which is gonna leave us with 6.28=2*x which gives you x(pi)= 3.14. For circle B we have 15.70=2*x*2.5 isolate x by first dividing 2.5 which leaves us again with 6.28=2x and x= 3.14.
B) The equation for area is A=piR^2. So again for circle A we have 63.585=x9^2. This one is harder but also are you sure that the area is 63.585 it's supposed to be 254.469 (We'll come back to this)
C) The observation you can make about the value of pi for circles A and B is that it stays consistent at 3.14
3x - 2y = 6
-2y = -3x + 6
y = (-3/-2)x + 6/-2
y = 3/2x - 3
B. Quadrant 2 you can tell because point J is in the upper left quadrant.
3 bags my g have a awesome day
