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tamaranim1 [39]
2 years ago
5

An ice cube at 0°C is placed in a very large bathtub filled with water at 30°C and allowed to melt, causing no appreciable chang

e
in the temperature of the bath water. Which one of the following statements is true?
A. The net entropy change of the system (ice plus water) is zero because no heat was added to the system
B. The entropy lost by the ice cube is equal to the entropy gained by the water
C. The entropy of the system (ice plus water) increases because the process is irreversible
D. The entropy of the water does not change because its temperature did not change
E. The entropy gained by the ice cube is equal to the entropy lost by the water​
Physics
1 answer:
Paladinen [302]2 years ago
6 0

Answer:

C. The entropy of the system (ice plus water) increases because the process is irreversible.

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At a particular instant, a hot air balloon is 100 m in the air and descending at a constant speed of 2.0 m/s. at this exact inst
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Answer:

86.4 m  horizontal from landing spot

Explanation:

Find out how long before the ball hits the ground

 vertical speed  of ball = -2  m/s     gravity = - 9.81 m/s^2

find time to hit ground from 100 m  

          ( height will be<u> zero</u> when it hits the ground)

<u>0 </u>=  100  - 2 t  - 1/2 ( 9.81) t^2

        use Quadratic Formula to find t = 4.32 seconds

              horizontal speed of ball = 20 m/s  

in 4.32 seconds it will travel horizontally   20  m/s * 4.32 s = 86.4 m

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1 year ago
Single Replacement: HCI + Zn
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1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
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Can the boiling point of water exceed 100c
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6 0
3 years ago
If stellar parallax can be measured to a precision of about 0.01 arcsec using telescopes on the Earth to observe stars, to what
marin [14]

Answer:

It corresponds to a distance of 100 parsecs away from Earth.

Explanation:

The angle due to the change in position of a nearby object against the background stars it is known as parallax.

It is defined in a analytic way as it follows:

       

\tan{p} = \frac{1AU}{d}

Where d is the distance to the star.

p('') = \frac{1}{d} (1)  

Equation (1) can be rewritten in terms of d:

d(pc) = \frac{1}{p('')} (2)

Equation (2) represents the distance in a unit known as parsec (pc).

The parallax angle can be used to find out the distance by means of triangulation. Making a triangle between the nearby star, the Sun and the Earth (as is shown in the image below), knowing that the distance between the Earth and the Sun (150000000 Km), is defined as 1 astronomical unit (1AU).

For the case of   (p('') = 0.01):

d(pc) = \frac{1}{0.01}

d(pc) = 100

Hence, it corresponds to a distance of 100 parsecs away from Earth.

<em>Summary:</em>

Notice how a small parallax angle means that the object is farther away.

Key terms:

Parsec: Parallax of arc second

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