Answer:
The value of g = 0.6168 m/s².
Explanation:
Given that,
On a planet X,
Length of the pendulum(L) = 0.25 meters,
Time period of the pendulum(T) = 4 seconds.
We have to find the 'g' value on the planet.
The 'g' value on a planet can be found by a pendulum with help of the formula,
T = 2π × 
From this, g = 4π² × 
Using the above formula and substituting the values,we get,
g = 0.6168 m/s².
The mass of the truck is needed because momentum=mass×velocity.
Answer:
Explanation:
Given:
P = 6.35 atm
= 1.01 × 10^5 × 6.35
= 6.434 × 10^5 N/m^2
As = 975 cm^2
D = 3.8 g/cm^2
M = 320 kg
Since the propellant volume is equal to the cross sectional area, As times the fuel length, the volumetric propellant consumption rate is the cross section area times the linear burn rate, bs , and the instantaneous mass flow rate of combustion, ms gases generated is equal to the volumetric rate times the fuel density, D
ms = D × As × bs
ms ÷ bs = M/L
M/L = 3.8 × 975
= 3705 g/cm
= 3.705 × 10^6 kg/m^3
Pressure = mass × g/area
= mass/length × time^2
t = sqrt(3.705 × 10^6/6.43 × 10^5)
= 2.4 s
Answer: Option B) chemical --> electrical
Explanation:
Batteries convert their stored chemical energy into electrical energy in order to power appliances.
So, the conversion of chemical energy to electrical energy explains how energy is conserved in nature, such that energy is neither created nor destroyed.
Answer:
a) Kinetic energies
K₁ = 1.2 J
K₂ = 7.5 J
b) The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s , K₂ = 7.5 J
c) K₂ -K₁ = 6.3 J
Explanation:
The kinetic energy (K) is that due to the movement of a body and is calculated as follows:
K = (1/2) m*v² (J)
Where :
m : the mass of the body ( kg)
v is the speed of the body (m/s)
Data
m₁ = m₂ = 0.006 Kg
v₁ = 20 m/s
v₂ = 50 m/s
a)Calculation of the kinetic energy
K₁ = (1/2) (m₁)*(v₁)²
K₁ = (1/2) (0.006)*(20)²
K₁ = 1.2 J
K₂= (1/2) (m₂)*(v₂)²
K₂ = (1/2) (0.006)*(50)²
K₂ = 7.5 J
b) K₂ ˃ K₁
The bullet that has the highest kinetic energy is the one with the highest speed , v = 50 m/s, K₂ = 7.5 J
c) Difference of their kinetic energies (K₂ -K₁)
K₂ -K₁ = 7.5 J - 1.2 J = 6,3 J
