What wires allow electrons to flow the easiest?
1 answer:
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Answer:
The correct answer is C. 45.5 lbs.
Explanation:
In a second class lever, the load is located between the point in which the force is exerted and the fulcrum.
The formula for any problem involving a lever is:
Where F_e is the effort force, d_e is the total length of the lever, F_l is the load that can be lifted and d_l is the distance between the point of the effort and the fulcrum.
The parameter of the formula that you need is F_l:
The conversion from feet to inches is 1 ft is equal to 12 inches. In this case, 5 ft are equal to 60 inches.
F_l=45.5 lbs
Answer:
E = 24000 N/C = 24 KN/C
Explanation:
The electric field experienced by a test charge is given by the following formula:
where,
E = Electric Field = ?
F = Force of attraction = 3 x 10⁻⁶ N
q = Charge on piece of lint = 1.25 x 10⁻¹⁰ C
Therefore, using these values in the equation, we get:
<u>E = 24000 N/C = 24 KN/C</u>