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3 years ago

Describe a scientific method

1 answer:

7 0

The process of <u>scientific method</u> involves making hypotheses , driving predictions from them as logical consequences , and then carrying out experiments or empirical observations based on those predictions. A hypotheses is a conjecture , based on knowledge obtained while seeking answers to the questions.

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What was the only option for getting the Apollo 13 astronauts back to Earth alive?

Vera_Pavlovna [14]

They got back in the Lunar Explorer Module

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3 years ago

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When observed from earth, how many oscillations does the pendulum on the spaceship undergo compared to the pendulum on earth in

Roman55 [17]

Answer: it’s Fewer oscillations.

Explanation:

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3 years ago

A constant force of 10 N is applied to an object. The object accelerates at a constant rate of 4 m/s2. What is the mass of the o

tatuchka [14]

Answer:

I think it is 2.5 kg.

Explanation:

I can say you do:

Fnet = m * a

So, you want to find mass:

m = Fnet / a

So, the answer you will receive is 2.5

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3 years ago

A block with a mass of 31.8 kg is pushed on a frictionless

OlgaM077 [116]

Answer: Total work done on the block is 3670.5 Joules.

Step by step:

Work done:

$W = F.d.\cos\theta$

With F the force, d the displacement, and theta the angle of action (which is 0 since the block is pushed along the direction of displacement, and cos 0 = 1)

$W = F.d$

Given:

F = 75 N

m = 31.8 kg

Final velocity $v_f = 15.3 \frac{m}{s}$

In order to calculate the Work we need to determine the displacement, or distance the block travels. We can use the information about F and m to first figure out the acceleration:

$F = ma\\\implies a=\frac{F}{m}=\frac{75 N }{31.8 kg}\approx 2.36 \frac{m}{s^2}\\$

Now we can determine the displacement from the following formula:

$d = \frac{1}{2}a^2+v_0t+d_0$

Here, the initial displacement is 0 and initial velocity is also 0 (at rest):

$d = \frac{1}{2}at^2\\$

Now we still have "t" as unknown. But we are given one more bit of information from which this can be determined:

$v_f = a\cdot t_f\\\implies t_f = \frac{v_f}{a} = \frac{15.2 \frac{m}{s}}{2.36 \frac{m}{s^2}}\approx 6.44 s$

(using vf as final velocity, and tf as final time)

So it takes about 6.44 seconds for the block to move. This allows us to finally calculate the displacement:

$d = \frac{1}{2}at^2=\frac{1}{2}2.36 \frac{m}{s^2}\cdot 6.44^2 s^2 \approx 48.94 m$

and the corresponding work:

$W = F\cdot d=75 N\cdot 48.94 m =3670.5J$

7 0

3 years ago

A van of mass 2500kg travelling at a velocity of 12 m/s collides with a stationary car of mass 700kg. The vehicles move together

Fiesta28 [93]

Answer: 9.375m/s

Explanation: This is an inelastic collision, so the formula is mv1+mv2=(m1+m2)v-final. My work is a follows:

2500kg(12m/s) + 700kg(0m/s)=(2500kg+700kg)(v-final)

30,000kg(m/s)+0=3200kg(v-final)

30,000kg(m/s)/3200kg=9.375m/s

5 0

3 years ago