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3 years ago

Describe a scientific method

1 answer:

7 0

The process of scientific method involves making hypotheses , driving predictions from them as logical consequences , and then carrying out experiments or empirical observations based on those predictions. A hypotheses is a conjecture , based on knowledge obtained while seeking answers to the questions.

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alina1380 [7]

Answer:

kalmadı artık yazmay ama artık gerek

6 0

3 years ago

Francesca, who likes physics experiments, dangles her watch from a thin piece of string while the jetliner she is in takes off f

Tom [10]

Answer:

$v_f = 82.3 m/s$

Explanation:

When a suspended string makes and angle of 25 degree while aircraft is accelerating on runway then we can use force equations to find the acceleration of the aircraft

So we will have

$T sin\theta = ma$

$T cos\theta = mg$

now from above two equations we have

$a = g tan\theta$

$a = (9.81) tan25$

$a = 4.57 m/s^2$

now if it took 18 s to take off we can have final speed of the aircraft given by

$v_f - v_i = at$

$v_f - 0 = (4.57)(18)$

$v_f = 82.3 m/s$

6 0

3 years ago

Compare the surface temperature of a red star with the temperature of a yellow star

inna [77]

The surface temperature of a red star is lower than the surface temperature of a yellow star.

Explanation:

For a red star, the peak of the wavelength of the emitted light is in the red spectrum, therefore the average peak wavelength is:

$\lambda = 680 nm = 680 \cdot 10^{-9} nm$

The corresponding temperature at the surface of the star can be found by using Wien's displacement law:

$T=\frac{b}{\lambda}$

where

$b=2.898\cdot 10^{-3} m\cdot K$ is a constant. Substituting, we find

$T_r=\frac{2.898\cdot 10^{-3}}{680\cdot 10^{-9}}\sim 4300 K$

For a yellow star, the peak of the wavelength of the emitted light is in the yellow spectrum, therefore the average peak wavelength is:

$\lambda = 580 nm = 580 \cdot 10^{-9} nm$

So we can use again the same equation to find the corresponding surface temperature of a yellow star:

$T_y=\frac{2.898\cdot 10^{-3}}{580\cdot 10^{-9}}\sim 5000 K$

Therefore, we see that the surface temperature of a red star is lower than the surface temperature of a yellow star.

Learn more about temperature:

brainly.com/question/1603430

brainly.com/question/4370740

#LearnwithBrainly

6 0

3 years ago

How long will it take 24 C of charge to flow in a 6.0 A circuit? O 0.25 S O 4.05 o 185

RoseWind [281]

Explanation:

charge=24

current =6.0

time=?

formula

c harge=current ×time

charge/current=time

24/6.0=time

4.05second=time

4 0

3 years ago

Determine the magnitude of the electric field at the point P. Express your answer in terms of Q, x, a, and k. Express your answe

Sav [38]

Complete Question

The question image is in the first uploaded image

Answer:

$E=\frac{KQ*4xa}{(x^2-a^2)^2}$

Explanation:

From the question we are told that

Distance b/w Q mid point and P is given as x

Generally the equation for magnitude of the electric field at the point P is given as

$E=\frac{kQ}{d^2}$

where

$k=\frac{1}{4\pi e_0}$

$d=x^2-a^2$

Therefore

$E= \frac{1}{4\pi e_0} \frac{Q}{(x^2-a^2)^2}- \frac{1}{4\pi e_0} \frac{Q}{(x^2+a^2)^2}$

$E= \frac{Q}{4\pi e_0} (\frac{1}{(x^2-a^2)^2}- \frac{1}{(x^2+a^2)^2})$

Therefore equation for magnitude of the electric field at the point P is

$E=\frac{KQ*4xa}{(x^2-a^2)^2}$

8 0

3 years ago