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Drupady [299]
3 years ago
10

What is the length of SA?

Mathematics
1 answer:
lukranit [14]3 years ago
6 0

Answer: 3 ft

Step-by-step explanation:

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How do you solve <br>x-3/(x-4) + 4= 3x/3
muminat
<span>x - 3/(x - 4) + 4 = 3 × x/3
</span>
<span><span>x^2−19/</span><span>x−4</span></span>=x
<span>Step 1: Multiply both sides by x-4.

</span><span><span><span>x^2</span>−19</span>=<span><span>x^2</span>−<span>4x

</span></span></span><span><span><span><span>x^2</span>−19</span>−<span>x^2</span></span>=<span><span><span>x^2</span>−<span>4x</span></span>−<span>x^2</span></span></span><span>(Subtract x^2 from both sides)

</span><span><span>−19</span>=<span>−<span>4x</span></span></span>
<span><span>−<span>4x</span></span>=<span>−19</span></span><span>(Flip the equation)

</span><span><span><span>−<span>4x</span></span><span>/−4</span></span>=<span><span>−19</span><span>/−4  </span></span></span>(Divide both sides by -4)<span>Answer.
x=<span>19/4
</span></span><span>Check answers. (Plug them in to make sure they work.)</span>













8 0
4 years ago
I need help on this. What is the slope of a line perpendicular to the line with equation y=1/6x -2?
svlad2 [7]
The slope of the given equation is 1/6. To find the perpendicular slope, all we need to do is take the negative reciprocal of it, which is -6. Therefore, the slope of a line perpendicular to the line with equation y = 1/6x - 2 is -6. Hope this helps and have a great day!
7 0
3 years ago
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Which of the following is one branch or part of the government?
baherus [9]

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Congress

Step-by-step explanation:

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3 years ago
10. Rays DA and DC are perpendicular. Point B lies in the interior of
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Answer:

<em><u>Rays DA and DC are perpendicular. Point B lies in the interior of ∠ADC.</u></em><em><u> </u></em>

Step-by-step explanation:

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u> </u></em><em><u>you</u></em><em><u> </u></em><em><u>✌️</u></em>

<em><u>Mark</u></em><em><u> </u></em><em><u>me as</u></em><em><u> </u></em><em><u>Brainleist</u></em><em><u> </u></em><em><u>✌️</u></em>

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