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Anika [276]
2 years ago
15

What is the scale factor if a 4" by 10" photograph is enlarged to a poster that is 1 ft. by 2.5 ft.?

Mathematics
1 answer:
Lelechka [254]2 years ago
7 0

Answer:

sorry I can't help you with this answer

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What value(s) of x will make each equation below true?
kvasek [131]

Answer:

a X=0

b X=0

c X= undetermined

5 0
2 years ago
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Alberto is painting a large triangle on one wall of his bedroom. The base of the triangle is 4 ft, and the height is 8 ft. It ta
N76 [4]

Answer:   3.2 qts

Step-by-step explanation:

A=1/2 * b *h

1/2 * 4*8 = 16 square foot

Area is 16 square foot

Multiply the area by the quarts of paint it takes to cover 1 square foot.

16 * 0.2 = 3.2 qts

4 0
3 years ago
A machine that produces ball bearings has initially been set so that the true average diameter of the bearings it produces is .5
lara [203]

Answer:

7.3% of the bearings produced will not be acceptable

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 0.499, \sigma = 0.002

Target value of .500 in. A bearing is acceptable if its diameter is within .004 in. of this target value.

So bearing larger than 0.504 in or smaller than 0.496 in are not acceptable.

Larger than 0.504

1 subtracted by the pvalue of Z when X = 0.504.

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.504 - 0.494}{0.002}

Z = 2.5

Z = 2.5 has a pvalue of 0.9938

1 - 0.9938= 0.0062

Smaller than 0.496

pvalue of Z when X = -1.5

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.496 - 0.494}{0.002}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.0668 + 0.0062 = 0.073

7.3% of the bearings produced will not be acceptable

4 0
3 years ago
Plz help 100 points
tekilochka [14]

Answer:

the answer is one line is increased by 1, and the other increased by 6

hope this helped :))

4 0
2 years ago
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Multiple choice easy question. Please answer.
Anton [14]

Answer:

I belive it should be # 3 i might be wrong thow.

Step-by-step explanation:

3 0
1 year ago
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