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Masja [62]
3 years ago
8

what is 31/50000 If the toxic quantity is 1.5 g of ethylene glycol per 1000 g of body mass, what percentage of ethylene glycol i

s fatal
Chemistry
1 answer:
Sveta_85 [38]3 years ago
7 0

Answer:

\%m=0.15\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed with the shown below formula:

\%m=\frac{m_{ethylene \ glycol}}{m_{ethylene \ glycol}+m_{body\ mass}}*100\%

We can use the given masses to obtain:

\%m=\frac{1.5g}{1.5g+1000g}*100\%\\ \\\%m=0.15\%

Best regards.

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                                              CnH₂n₊₂          ------- (1)
As m/z = 380
So,
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Or,
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                                                   14n  =  380 - 2

                                                   14n  =  378

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                                                       n  =  27
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                                              C₂₇H₍₂₇ₓ₂₎₊₂

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