Answer: 0.2885J/g°c
Explanation:
Loss of heat of metal = Gain of heat by the water
Therefore
-Qm = +Qw
Where
Q = mΔTCp
Q = heat
M= mass
ΔT = T.f - Ti
Ti= initial temperature
T.f= final temperature
Cp= Specific heat (m is metal, w is water)
-Qm = +Qw
-[m(T.f-Ti)Cpm] = m(T.f-Ti)Cpw
Therefore
-[83.2g(28.42-90.31)Cpm] = 41.82g(28.42-
19.93)4.194J/g°c
Cpm = 1485.54÷ 5149.25
Cpm = 0.2885J/g°c
Therefore , the specific heat of the metal is 0.2885J/g°c
Answer:

Explanation:
The quantity of moles of ethanol in the solution is:


The mass and volume of ethanol in the solution are, respectively:




The difference between the total volume of water and ethanol mixed to prepare the solution and the actual volume of solution is:


It is better for the whales to go where the whales have the ability to dive longer and deeper to find cooler water.
Answer:
%age Yield = 85.36 %
Solution:
The Balance Chemical Reaction is as follow,
C₆H₁₂O + Acid Catalyst → C₆H₁₀ + Acid Catalyst + H₂O
According to Equation ,
100 g (1 mole) C₆H₁₂O produces = 82 g (1 moles) of C₆H₁₀
So,
4.0 g of C₆H₁₂O will produce = X g of C₆H₁₀
Solving for X,
X = (4.0 g × 82 g) ÷ 100 g
X = 3.28 g of C₆H₁₀ (Theoretical Yield)
As we know,
%age Yield = (Actual Yield ÷ Theoretical Yield) × 100
%age Yield = (2.8 g ÷ 3.28 g) × 100
%age Yield = 85.36 %
<span>Your final answer would be C4H10O2, which equals 90amu</span>