Answer:
90 minutes
Explanation:
The half life of a first order reaction is;
t1/2 = ln(2) / k
To solve for t;
The integral rate expression for a first order reaction is;
ln[A] = ln[Ao] - kt
t = 60 minutes
Final Concentration = [A] = 100 - 37 = 63
Initial Concentration = [Ao] = 100
ln(63) = ln(100) - k (60)
k (60) = ln (100) - ln(63)
k = 0.4620 / 60 = 0.0077
Inserting the value of k in the half life equatin;
t1/2 = ln(2) / 0.0077 = 90 minutes
