Answer:
.0924 moles of NaCl
Explanation:
So you know you have 5.4 g of NaCl and you need to know how many moles there are in this amount of NaCl
- You'll need to find the atomic mass of the compound NaCl to help you solve for moles
- Sodium (Na) on the periodic table has a mass of 22.99
- Chlorine (Cl) on the periodic table has a mass of 35.45
Add these two together----> 22.99 + 35.45 = 58.44
Now you can calculate for moles
<u>Written-out method:</u>
<u>5.4 grams of NaCl | 1 mole of NaCl </u>
| 58.44 grams NaCl = .0924 moles of NaCl
<u>Plug into calculator method:</u>
(5.4 g of NaCl/ 58.44g NaCl= .0925 moles)
Answer:
Ammonium bromide can be prepared by the direct action of hydrogen bromide on ammonia. It can also be prepared by the reaction of ammonia with iron(II) bromide or iron(III) bromide, which may be obtained by passing aqueous bromine solution over iron filings.
Explanation:
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3 of them left and i just need points lol sorrrry
Answer:
they have the same molar solubility at 44.5 degrees celsius
Overuse of the same chemicals can result in the pest becoming immune to the pesticides.