Substances that are less dense than water will_____ and substances with a density that is greater than 1.00 g/ml will___

Evaluate ( a=2 b=3)...3a - 2b =

skad [1K]

Hey!

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Steps To Solve:

~Substitute

3(2) - 2(3)

~Subtract

6 - 6

~Simplify

0

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Answer:

$\Large\boxed{\mathsf{0}}$

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Hope This Helped! Good Luck!

4 0

3 years ago

Read 2 more answers

Enter your answer in the provided box. an aqueous solution containing 10 g of an optically pure substance was diluted to 500 ml

sladkih [1.3K]

Answer:

[α] = -77.5° / $\frac{\textup{dm-g}}{\textup{mL}}$

Explanation:

Given;

Mass of optically pure substance in the solution = 10 g

Volume of water = 500 mL

Length of the polarimeter, l = 20 cm = 20 × 0.1 dm = 2 dm

measured rotation = - 3.10°

Now,

The specific rotation ( [α] ) is given as:

[α] = $\frac{\alpha}{c\times l}$

here,

α is the measured rotation = -3.10°

c is the concentration

or

c = $\frac{\textup{Mass of optically pure substance in the solution}}{\textup{Volume of water}}$

or

c = $\frac{10}{500}$

or

c = 0.02 g/mL

on substituting the values, we get

[α] = $\frac{-3.10^o}{0.02\times2}$

or

[α] = -77.5° / $\frac{\textup{dm-g}}{\textup{mL}}$

7 0

3 years ago

A containing vessel holds a gaseous mixture of nitrogen and butane. Thepressure in the vessel at 126.9 Cis 3.0 atm. At 0 C, the

Viefleur [7K]

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

A vessel contains a gaseous mixture of nitrogen and butane. At 126.9 °C (400.1 K) the pressure is due to the mixture is 3.0 atm.

We can calculate the total number of moles using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{3.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.091 mol/L \times V$

At 0 °C (273.15 K), the pressure due to the gaseous nitrogen is 1.0 atm.

We can calculate the moles of nitrogen using the ideal gas equation.

$P \times V = n \times R \times T\\\\n = \frac{P \times V}{R \times T} = \frac{1.0 atm \times V}{0.082 atm.L/mol.K \times 400.1 K} = 0.030 mol/L \times V$

The mole fraction of nitrogen in the mixture is:

$X(N_2) = \frac{0.030 mol/L \times V}{0.091 mol/L \times V} = 0.33$

A vessel that contains a mixture of nitrogen and butane has a pressure of 3.0 atm at 126.9 °C and a pressure of 1.0 atm at 0 °C. The mole fraction of nitrogen in the mixture is 0.33.

Learn more: brainly.com/question/2060778

5 0

3 years ago

What is dependent on the ability of water molecules to form hydrogen bonds with other molecules besides water

Vikentia [17]

Answer:

The ability of water molecules to form hydrogen bonds with other molecules besides water is the universality of water as a solvent.

Explanation:

hope it helps you :)

7 0

2 years ago

Fill in the blank with the correct answer. The longer the handle the __________ the mechanical advantage and the greater the inc

ASHA 777 [7]

Answer:

Greater

Explanation:

The longer the handle, the greater the mechanical advantage and the greater the increase in force that is applied to the bolt.

Mechanical advantage is the rate at which force is multiplied.

It simply compares the output force to the input force.
M.A is the force increasing tendency of a tool.
The longer the handle, the more the mechanical advantage and the lesser the applied force.

7 0

2 years ago

Substances that are less dense than water will_____ and substances with a density that is greater than 1.00 g/ml will____

Substances that are less dense than water will_ and substances with a density that is greater than 1.00 g/ml will