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erik [133]
3 years ago
6

Jin ran 15.2 miles over the weekend.he ran 6.75 miles on saturday.how many miles did he run on saturday?

Mathematics
2 answers:
Ivan3 years ago
5 0
For order you to solve that all you half to do is subtract 6.75 from 15.2.
ivolga24 [154]3 years ago
4 0

Answer:

Jin ran 8.45 miles on Saturday.

Step-by-step explanation:

We know that Jin ran 15.2 miles over the weekend. We can turn this into an equation :

15.2(miles)=Saturday+Sunday

Being Saturday the total miles he ran on Saturday and Sunday the total miles he ran on Sunday.

Given that he ran 6.75 miles on Saturday (It's a data from the exercise) we can replace this in the equation :

15.2(miles)=6.75(miles)+Sunday

Solving the equation :

15.2(miles)=6.75(miles)+Sunday

Sunday=15.2(miles)-6.75(miles)=8.45(miles)

We find that Jin ran 8.45 miles on Sunday

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2 years ago
I WILL GIVE BRAINLIEST
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The ΔPQR is right-angled at P, and PN is an altitude. If QN = 12 in and NR = 6 in, find PN, PQ, PR.
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3 years ago
A woman is q years old while her son is p years old. the sum of their ages is equal to twice the difference of their ages. the p
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Step-by-step explanation:

Given

q + p = 2(q - p)

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I used q-p as the difference as logically the woman will be older than her son.

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qp = 675

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Using equation 2,

q =  \frac{675}{p}

substitute this equation into equation 1.

\frac{675}{p}  + p = 2( \frac{675}{p}  - p) \\  \frac{675}{p}  + p =  \frac{1350}{p}  - 2p \\  \frac{675}{p}   -  \frac{1350}{p}  =  - 2p - p \\  - 3p =  -  \frac{675}{p}  \\    - 3p \times p =  - 675 \\  - 3 {p}^{2}  =  - 675 \\  {p}^{2}  =  - 675 \div  - 3 \\  {p}^{2} = 225 \\ p =  \sqrt{225}   \\  = 15

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Therefore the woman is 45 years old while her son is 15 years old.

3 0
3 years ago
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