What are four factors that can affect the amount of friction between two objects
1 answer:
As the Force of friction is equal to 
µ
by using the Law of Action Reaction; as the force normal is the conterforce of gravity
µ
µ
Therefore, by looking at the equation we can infer that
The force of friction is directly proportional to the mass, gravitational constant, and the co-efficent of friction
Because the gravitational constant is dependant on gravitation, a planet's mass and radius also affect the force of friction
But DO NOTE:
That the co-effecient of friction is only applicable between two rubbing surfaces and unaffected by gravitational constants.
If you found this helpful, please rate it as "Brainiest"
Also if this need further explaining, please comment below
Therefore, by looking at the equation we can infer that
The force of friction is directly proportional to the mass, gravitational constant, and the co-efficent of friction
Because the gravitational constant is dependant on gravitation, a planet's mass and radius also affect the force of friction
But DO NOTE:
That the co-effecient of friction is only applicable between two rubbing surfaces and unaffected by gravitational constants.
If you found this helpful, please rate it as "Brainiest"
Also if this need further explaining, please comment below
You might be interested in
<u>Answer:</u>
<em>Thunderbird is 995.157 meters behind the Mercedes</em>
<u>Explanation:</u>
It is given that all the cars were moving at a speed of 71 m/s when the driver of Thunderbird decided to take a pit stop and slows down for 250 m. She spent 5 seconds in the pit stop.
Here final velocity
initial velocity distance
Distance covered in the slowing down phase =
The car is in the pit stop for 5s
After restart it accelerates for 350 m to reach the earlier velocity 71 m/s
total time=
Distance covered by the Mercedes Benz during this time is given by
Distance covered by the Thunderbird during this time=
Difference between distance covered by the Mercedes and Thunderbird
=
Thus the Mercedes is 995.157 m ahead of the Thunderbird.
Explanation:
Since, it is mentioned the there occurs no change in the temperature. This also means that there will occur no change in thermal energy of the system.
Hence, = 0. And, as
= 0 then there will be no work involved. This means that total energy added to the house will return to the outside air as heat.
Therefore,
Q = -(19000 J + 2000 J)
= -21000 J
or, |Q| = 21000 J
Thus, we can conclude that the magnitude of the energy transfer between the house and the outside air is 21000 J.
In physical chemistry, the terms body-centered cubic (BCC) and face-centered cubic (FCC) refer to the cubic crystal system of a solid. Each solid is made up simple building blocks called lattice units. There are different layouts of a lattice unit.
It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.
It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.