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Maru [420]
3 years ago
7

Calculate how much protein is contained in three sausages. Show all working​

Biology
2 answers:
Ksju [112]3 years ago
6 0

The amount of protein contained in  three ( 3 ) sausages is approximately 15 grams

Sausages are made from meat which includes ;

pork, beef and poultry.

The amount of protein present in a sausage depends on the type of sausage and weight of  the sausage.

Hence for the purpose of this question I will base my calculation on a 1 -ounce pork sausage

A single  1 - ounce pork sausage contains about 5 grams of proteins

∴ Three sausages = 3 * 5 = 15 grams of protein

Therefore the amount of protein contained in three sausages = 15 grams

learn more about protein : brainly.com/question/11006427

Vedmedyk [2.9K]3 years ago
5 0

Answer:

14gm  

Explanation:

14gm

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the couple is also concerned about their child inheriting hemophilia, another rare disease, which is x-linked. natalie’s brother
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Hemophilia is a recessive X-linked condition and is inherited from parents. . The probability that Natalie and Daniel’s first child has hemophilia is<u> 1/4</u>, not 1/8. The statement is<u> false.</u>

<h3>What is an X-linked gene?</h3>

When talking about sex-linked genes, we refer to all those genes located in one of the sex-chromosomes and not in the somatic ones.

X-linked genes are the genes located specifically in the X sex chromosome.

Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations.

According to this, X-linked genetic disorders will be inherited as well.

  • Men have a high probability of being affected since they only have one copy of the X chromosome.
  • In women, the effect of the mutation might be musk in heterozygous state if the mutation is recessive.

Hemophilia is a recessive X-linked disorder, which means it is coded by the recessive allele.

  • X+ ⇒ X chrosomosome with Dominant allele
  • X- ⇒ X chrosomosome with Recessive allele

<u>Genotype              Phenotype</u>

X+X+                   Healthy woman

X+X-                    Healthy carrier woman

X-X-                     Hemophilic woman

X+Y                      Healthy man

X-Y                       Hemophilic man

Let us make a pedigree of these families,

<u>Natalie's family</u>:

Mother         healthy carrier          X+X-

Father          healthy                      X+Y

Brother        hemophilic                X-Y  

Natalie         Healthy                     X+X- or X+X+  

Natalie has 1/2 chances of being carrier X+X- and 1/2 of being X+X+.

<u>Daniel's family</u>:

Mother         healthy carrier          X+X-

Father          hemophilic                X-Y  

Sister           hemophilic                X-X-

Daniel          Healthy                      X+Y

He has 1/2 chances of being healthy X+Y and 1/2 of being affected X-Y.

According to the product probability rule, if events A and B are independent from each other, the probability of occurrence of both events together is

P(A∩B) = P(A) x P(B)

In this case,

  • event A is Daniel being affected ⇒ 1/2
  • event B is Natalie being carrier ⇒ 1/2

P(A∩B) = P(A) x P(B) = 1/2 x 1/2 = 1/4

The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is<u> false.</u>

You can learn more about X-linked genes at

brainly.com/question/12420228

brainly.com/question/14704182

brainly.com/question/1387724

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