The answer to your question is,
E. Equatorial Pacific Ocean
-Mabel <3
Answer:
to learn about its history/formation
Explanation:
Prostatic acid phosphatase was purified from prostatic fluid. Monospecific antisera to the purified acid phosphatase was then produced in rabbits. When antibody was coupled with acid phosphatase, the enzymatic activity was markedly stabilized against pH and temperature degradation. Both acid phosphatase and rabbit anti acid phosphatase were non specifically coupled to Sepharose-4B using cyanogen bromide. Under these circumstances slight stability occurred when antibody was bound to Sepharose, and then acid phosphatase added to the gel antibody complex. When acid phosphatase was complexed to Sepharose, no stabilization occurred.
Answer:
B. 0.42
Explanation:
Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1
According to the given information, the frequency of one allele in the population is= 0.7
This means that the frequency of the other allele would be= 1-0.7 = 0.3
Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42
