Step-by-step explanation:
,8x.,edn bu3d,ysw ,h3db,h7db3u,ftni9,4nz8ienzj8z 83 J83s z9j2s 0/$.plex9?wzok)#(?
Answer:
c = 
Step-by-step explanation:
Given
R= 
Clear the radical by squaring both sides
R² = b² - 4ac ( subtract b² from both sides )
R² - b² = - 4ac ( multiply all terms by - 1 )
b² - R² = 4ac ( divide both sides by 4a )
= c
9514 1404 393
Explanation:
This is a self-answering question: you solve it by graphing the equations.
<em>The solution is where the lines intersect</em>. The point of intersection of the lines is the point that satisfies all the equations for the lines, hence is a solution to the system. If they do not intersect, there are no solutions. If the lines are coincident, there are an infinite number of solutions.
__
The equations can be graphed by any of a number of methods. (My favorite is to let a graphing calculator do it.) The method of choice depends on the coefficients and the form the equations are given in. Methods of graphing are a topic for a more lengthy discussion.
Question # 1
Answer:

Step-by-step explanation:
Given the expression

∵ 
∵ 








Therefore,

Question # 2
Answer:

Step-by-step explanation:
Given

∵ 
∵ 










Therefore,

Answer:
B) 628.32 cm cubed
Step-by-step explanation:
we know the formula to find the volume of a cylinder is π*r^2*h
where r is the radius and h is the height.
the equation would look like this
π*5^2*8
π*25*8
π*200
628.32 cm