In each pair of compounds, pick the one with the higher vapor pressure at a given temperature. Explain your reasoning.

Chemistry

1 answer:

Gnoma [55]3 years ago

8 0

Answer:

The answer is:

$PART \ A: CH_4\\\\PART \ B: CH_30H\\\\PART \ C: H_2CO$

Explanation:

Parts A:

The vapor pressure is higher in $CH_4$ because it is non-polar, while $CH_3Cl$ is polar. $CH_4$ has a lower molar weight as well.

Part B:

Although hydrogen bonding is found in both commodities, the vapor pressure is higher because of the smaller molar mass of $CH_30H$ .

Part C:

$H_2CO$ does not show hydrogen due to the increased vapor pressure

$CH_3OH$ bonding.

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Answer:

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Explanation:

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Then,

$\dfrac{\text{rate}_{2}}{\text{rate}_{1}} = \left (\dfrac{1}{2}\right ) \left (\dfrac{1}{2}\right )^{2} = \dfrac{1}{2}\times\dfrac{1}{4} = \dfrac{1}{8}\\\\\text{rate}_{2} = \dfrac{1}{8}\times \text{rate}_{1}= \dfrac{1}{8}\times \text{0.0080 mol$\cdot$L$^{-1}$s$^{-1}$} = \textbf{0.0010 mol$\cdot$L$^{-1}$s$^{-1}$}\\\\\text{The new rate is $\large \boxed{\textbf{0.0010 mol$\cdot$L$^\mathbf{{-1}}$s$^{\mathbf{-1}}$}}$}$