<em>Sulphur </em><em>Trioxide</em><em> </em><em>=</em><em> </em><em>So</em><em>3</em>
<em>Sodium</em><em> Hydroxide</em><em> </em><em>=</em><em> </em><em>NaoH</em>
Answer:
yes, that is not a question, that's a statement
Answer:
The mass of the water in the container is 139.187g
Explanation:
During this process there will not be lost heat. But heat lost of silver is equal to heat won of water
q(lost, silver) = q(gained, water)
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
⇒mass of silver = 63.3g
⇒Cpsilver = 0.24J/g °C
⇒initial temperature silver = 384.4 K
⇒ final temperature silver = 292.4 K
⇒mass of water = TO BE DETERMINED
⇒Cpwater = 4.184 J/g °C
⇒initial temperature water = 290.0 K
⇒final temperature = 292.4 K
-mass * Cpsilver * (T2-T1) = mass * Cpwater * (T2-T1)
-63.3 * 0.24 * (292.4-384.4) = mass * 4.184 * (292.4 - 290.0)
-1397.664 = mass * 0.24 *2.4
mass water = 139.187g
The mass of the water in the container is 139.187g
Answer:
590 g CaCl₂
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
5.3 mol CaCl₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Ca - 40.08 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of CaCl₂ - 40.08 + 2(35.45) = 110.98 g/mol
<u>Step 3: Convert</u>
<u />
= 588.194 g CaCl₂
<u>Step 4: Check</u>
<em>We are given 2 sig figs. Follow sig fig rules and round.</em>
588.194 g CaCl₂ ≈ 590 g CaCl₂
