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son4ous [18]
4 years ago
9

In the reaction A + B C, doubling the concentration of A doubles the reaction rate and doubling the concentration of B does not

affect the reaction rate. What is the rate law for this reaction?
A) rate = k[B]
B)rate = k[A]2
C)rate = k[A][B]
D)rate = k[A]
Chemistry
1 answer:
Kitty [74]4 years ago
6 0
Here, the rate of reaction would be: rate = k[A]

In short, Your Answer would be Option D

Hope this helps!
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1 If 5.80 L of gas is collected at a pressure of 92.0 kPa, what volume will the same gas occupy at 101.3 kPa if the temperature
Anni [7]

Answer:

The volume that the same gas will occupy at 101.3 kPa if the temperature is kept constant is 5.27 L.

Explanation:

As the volume increases, the particles (atoms or molecules) of the gas take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law that says:

"The volume occupied by a given gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P * V = k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case, you have:

  • P1= 92 kPa
  • V1= 5.80 L
  • P2= 101.3 kPa
  • V2= ?

Replacing:

92 kPa* 5.80 L= 101.3 kPa* V2

and solving, you get:

V2=\frac{92 kPa* 5.80 L}{101.3 kPa}

V2= 5.27 L

<u><em>The volume that the same gas will occupy at 101.3 kPa if the temperature is kept constant is 5.27 L.</em></u>

4 0
3 years ago
How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
Vika [28.1K]

Answer:

Explanation:

we know that specific heat is the amount of heat required to raise the  temperature of substance by one degree mathmeticaly

Q=mcΔT

ΔT=T2-T1

ΔT=26.8-10.2=16.6

C for water is 4.184

therefore

Q=1.00*4.184*16.6

Q=69.4 j

now we have to covert joule into calorie

1 calorie =4.2 j

x calorie=69.4 j/2

so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius

6 0
3 years ago
Calculate the molar mass lead(ll) nitrate,Pb(NO3)2
SVETLANKA909090 [29]
Refer periodic table
Pb= 207.2
N=14
O= 16
207.2 \: + (14 \times 2) + (16 \times 6)
=331.2gmol
6 0
4 years ago
Phenol, c6h5oh, is a stronger acid than methanol, ch3oh, even though both contain an o]h bond. Draw the structures of the anions
timurjin [86]

In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure.  They are created by moving electrons in double or triple bonds, and not atoms.

Phenol, C_6H_5OH and methanol, CH_3OH both are alcohols  that contain an -OH group attached to carbon atom.

Due to loss of 1 H from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1 H it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.

The structures of the anions resulting from loss of 1 H from phenol and methanol is shown in the image.

8 0
3 years ago
Empirical formula of a compound if a 50.0 g sample of it contains 9.1g Na ,20.6 g Cr ,and 22.2 g O
denpristay [2]

Answer:

The empirical formula of a compound is Na2Cr2O7

Explanation:

Empirical formula is defined as the lowest ratio of elements present in any substance. In order to determine the empirical formula for a substance containing these elements we have to follow some steps.

1.In the first step, we have to divide the given mass of an element with its molecular mass to convert the mass to moles.

No. of moles of Na=Given Mass of Na/Molecular Mass of Na=9.1/23=0.396

Similarly, the moles of Cr and O in that compound were calculated and found as 0.396 and 1.3875, respectively.

2. Then the next step is to determine the lowest moles and divide all the moles with that lowest mole. As here the lowest mole is 0.396. So on dividing the moles of Na, Cr and O with 0.396, we will obtain the ratio as 1:1:3.5.

3. As the ratio consists of a fractional number, we have to multiply it with the smallest possible integer to convert it to whole number. In this case, if we multiply it with 2 , we will get the ratio as 2:2:7.

Thus, the empirical formula for the compound can be written as Na2Cr2O7.

5 0
4 years ago
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