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ollegr [7]
3 years ago
13

Which describes the correct number and types of atoms in this molecular structure?

Chemistry
1 answer:
DanielleElmas [232]3 years ago
5 0

Correct answer is five C, eight H, and two O

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Which of earth's spheres is most affected by weathering and erosion
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Answer: the hydrosphere

Explanation:

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The atmosphere is a(n) _____. <br> 1. element <br> 2. compound <br> 3. mixture
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The atmosphere is a mixture of gasses.
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A closed flask contains gas at STP. If the temperature is raised to 400 K what will the pressure be in atm?
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The answer is 1.5 atm

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2 years ago
Answer the question briefly: How can atom collapse and why are atoms stable?
kykrilka [37]

The nuclei of atoms become unstable when the repelling forces of the protons cannot be balanced by the number of neutrons in the nucleus. It then re-arranges itself randomly to a more stable configuration by emitting any of a series of particles. During radioactive decay, an atom does not collapse.

Since an atom is mostly empty space - that is it’s nucleus is relatively distant from the electron shells so, in the presence of extreme forces such as gravity inthe collapse of a large star, the inward pressures on the atom overcome the natural balance of the atomic structure and the ‘empty space’ disappears as nuclei are mashed together by the intense pressures and a neutron star is formed. Under even more external pressure, even the neutron star can collapse to form a black hole.

8 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
3 years ago
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