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Scrat [10]
3 years ago
7

A basketball player scored 26 times during one game. She scored a total of 51 points, two for each two-point shot and one for ea

ch free throw. How many two-point shots did she make? How many free throws?
Mathematics
2 answers:
gulaghasi [49]3 years ago
6 0
She scored alot but she made 25 two point shots and one free throw

 f+t+26
1f+2t=51
1x1=1  2x25=50  together that makes 51 points and she scored 26 times
alekssr [168]3 years ago
4 0

Answer: she scored 26 points

Step-by-step explanation:

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<img src="https://tex.z-dn.net/?f=%20express%20%5C%3A%20%20%5C%3A%20%5Csin%282x%29%20%20-%20%20%5Csqrt%7B3%7D%20%20%5Ccos%282x%2
gizmo_the_mogwai [7]

Answer:

α = π/3

γ = 2

x = -3π/4, -5π/12, π/4, 7π/12

Step-by-step explanation:

Easiest way to do this is in reverse.

γ sin(2x − α)

Angle sum/difference formula:

γ (cos α sin(2x) − sin α cos(2x))

Distribute:

γ cos α sin(2x) − γ sin α cos(2x)

Matching the coefficients:

γ cos α = 1

γ sin α = √3

Solve the system of equations.  Divide to eliminate γ:

tan α = √3

α is between 0 and π/2, so:

α = π/3

γ = 2

sin(2x) − √3 cos(2x) = 1

Using the identity from before:

2 sin(2x − π/3) = 1

Solving:

sin(2x − π/3) = 1/2

2x − π/3 = π/6 + 2kπ or 5π/6 + 2kπ

2x = π/2 + 2kπ or 7π/6 + 2kπ

x = π/4 + kπ or 7π/12 + kπ

x is between -π and π, so:

x = -3π/4, -5π/12, π/4, 7π/12

7 0
3 years ago
The frequency table was made using a box containing slips of paper. Each slip of paper was numbered 0, 1, 2, 3, or 4.
inna [77]
In order to make a frequency plot first we need to find the proportion of each outcome.

Total number of results = 15+20+5+5+5 = 50

Frequency of 0 = 15
Proportion of 0 = 15/50 = 0.3

Frequency of 1 = 20
Proportion of 0 = 20/50 = 0.4

Frequency of 2 = 5
Proportion of 2 = 5/50 = 0.1

Frequency of 3 = 5
Proportion of 3 = 5/50 = 0.1

Frequency of 4 = 5
Proportion of 4 = 5/50 = 0.1

Now we need to plot the data on a frequency plot. The x-axis shows the outcomes from 0 to 4 and y-axis shows the frequency of each outcomes. The frequency plot is shown in the figure attached with.

4 0
3 years ago
Read 2 more answers
X-4[x-2(x+6)]=5x+3<br><img src="https://tex.z-dn.net/?f=x%20-%204%20%20%20%5B%20%20x%20-%202%28x%20%2B%206%29%5D%20%20%3D%205x%2
pshichka [43]

The equivalence of the equation is 5x + 48 = 5x + 3.

Since 48 cannot be equal to 3, hence there are no solution.

<h3>What is the value of x?</h3>

Given the equation; x-4[ x - 2( x + 6) ] = 5x + 3

We remove the parentheses

x-4[ x - 2( x + 6) ] = 5x + 3

x-4[ x - 2x - 12 ] = 5x + 3

x - 4x + 8x + 48 = 5x + 3

5x + 48 = 5x + 3

We can go further and collect like terms

5x - 5x + 48 = 3

48 ≠ 3

Since 48 cannot be equal to 3, hence there are no solution.

Learn more about equations here: brainly.com/question/14686792

#SPJ1

7 0
2 years ago
What is the greatest common factor of 30a^2b^4 and 24ab^3?
Readme [11.4K]
30a^2b^4 GCF = 2
24ab^3 GCF = 3
6 0
3 years ago
Find the probability of drawing 3 Aces at random from a deck of 52 ordinary playing cards if the cards are:_________
Minchanka [31]

Answer:

A) 1/2197

B) 1/5525

Step-by-step explanation:

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome.

Since there are 52 random cards in a deck of card, the total outcome will be 52.

a) Also in a deck of card, there are 4 aces. If we are to select 3 aces with replacement, this means that each time we pick up an ace from the card, it was returned.

Pr(drawing an ace) = 4/52

Pr(drawing 3 aces and replacing it) = 4/52 *4/52*4/52

Pr(drawing 3 aces and replacing it) = 64/140,608

Pr(drawing 3 aces and replacing it) = 1/2197

b) If we pick 3 aces without replacement then each time we pick an ace, the total number cards keeps reducing.

Pr(picking the first ace) = 4/52

Pr(picking the second ace without replacing) = 3/51 (Since we didn't replace the first one, the total ace in the deck of card will reduce to 3 and the total will be 51)

Pr(picking the third ace without replacing) = 2/50 (since we didn't replace the first two aces, the total ace in the deck of card will reduce to 2 and the total will be 50)

Pr(drawing 3 aces without replacement) =  4/52*3/51*2/50

Pr(drawing 3 aces without replacement) =  24/132,600

Pr(drawing 3 aces without replacement) = 1/5525

5 0
3 years ago
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