01:28:29

A 100 meter rope is 20 kg and is stretched with a tension of 20 newtons. If one end of the rope is vibrated with small amplitude

dezoksy [38]

Answer:

The velocity waves before rain is 10 m/s

The velocity of wave after the rope soaked up 5 kg more is 8.944 m/s

Solution:

As per the question:

Length of the rope, l = 100 m

Mass of the rope, m = 20 kg

Force due to tension in the rope, $T_{r} = 20 N$

Frequency of vibration in the rope, f = 10 Hz

Extra mass of the rope after being soaked in rain water, m' = 5 kg

Now,

In a rope, the wave velocity is given by:

$v_{w} = \sqrt{\frac{T_{r}}{M_{d}}}$ (1)

where

$M_{d}$ = mass density

Mass density before soaking, $M_{d} = \frac{m}{l} = \frac{20}{100} = 0.20$

Mass density after being soaked, $M_{d} = \frac{m + m'}{l} = \frac{25}{100} = 0.25$

Initially, the velocity is given by using eqn (1):

$v_{w} = \sqrt{\frac{20}{0.20}} = 10 m/s$

The velocity after being soaked in rain:

$v_{w} = \sqrt{\frac{20}{0.25}} = 8.944 m/s$

3 0

3 years ago

The Dodgers are up at bat during the World Series. Joc Pederson swings his baseball bat and it collides perfectly with the baseb

arsen [322]

Answer:

According to Newton's third law, for every action force there is an equal (in size) and opposite (in direction) reaction force. ... The baseball forces the bat to the left; the bat forces the ball to the right. Together, these two forces exerted upon two different objects form the action-reaction force pair.

8 0

3 years ago

A projectile is launched at an angle of 60° above the horizontal. compared to the vertical component of the initial velocity of

jeka94

Equal to zero. Because at maximum height before it comes down, it experiences a momentary stop

8 0

3 years ago

The drawing shows a plot of the output emf of a generator as a function of time t. The coil of this device has a cross-sectional

adell [148]

This question is incomplete, the missing image uploaded along this answer below;

Answer:

a) frequency is 2.381 Hz

b) the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field is 0.5199 T

Explanation:

Given that;

cross sectional Area A = 0.018 m²

Number of turns N = 200

from the diagram. maximum time T = 0.42 sec

a) the frequency f of the generator in hertz

frequency = 1 / T

we substitute

frequency = 1 / 0.42 = 2.381 Hz

Therefore, frequency is 2.381 Hz

b) the angular frequency in rad/s

angular speed ω = 2πf

we substitute

ω = 2π × 2.381

ω = 14.96 rad/s

Therefore, the angular frequency/speed is 14.96 rad/s

c) the magnitude of the magnetic field.

to determine the magnitude of the magnetic field, we use the following expression;

e = NBAω

from the diagram, e = 28.0 V

so we substitute

28.0 V = 200 × B × 0.018 × 14.96

28 = 53.856B

B = 28 / 53.856

B = 0.5199 T

Therefore, the magnitude of the magnetic field is 0.5199 T

6 0

3 years ago

When a board with a box on it is slowly tilted to larger and larger angle, common experience shows that the box will at some poi

nydimaria [60]

Answer:

Correct option is A - The force of kinetic friction is smaller than that of static friction, but Fg remains the same.

Explanation:

(A) The force of kinetic friction is smaller than that of static friction, but Fg remains the same

6 0

3 years ago