For this case we first think that the skateboard and the child are one body.
We have then:
1 = jug
2 = skateboard + boy
By conservation of the linear amount of movement:
M1V1i + M2V2i = M1V1f + M2V2f
Initial rest:
v1i = v2i = 0
0 = M1V1f + M2V2f
Substituting values
0 = (7.8) (3.2) + (M2) (- 0.65)
0 = 24.96 + M2 (-0.65)
-24.96 = (-0.65) M2
M2 = (-24.96) / (- 0.65) = 38.4 kg
Then, the child's mass is:
M2 = Mskateboard + Mb
Clearing:
Mb = M2-Mskateboard
Mb = 38.4 - 1.9
Mb = 36.5 Kg
answer:
the boy's mass is 36.5 Kg
Answer:
Explanation:
Theorem of Binomial Distribution will apply here.
n = 29 , p = .67 , q = 0.33
mean = np = 29 x .67 = 19.43
Standard Deviation = √npq
= √29 x .67 x .33
= √6.4
= 2.53
=
Answer:
rpm
Explanation:
Given that rotational kinetic energy = 
Mass of the fly wheel (m) = 19.7 kg
Radius of the fly wheel (r) = 0.351 m
Moment of inertia (I) = 
Rotational K.E is illustrated as 





Since 1 rpm = 



Answer:
The action of rotating around something like for ex.. Child A stands in the middle of a room while Child B goes around Child A, Child B is rotating around Child A. Another ex. is; The earth rotates around the sun every 365 days the earth is rotating or going around the sun in a circle. So rotating to me is the act of rotating around something in any way shape or form.
PS: A middle schooler answered this so if you don't wanna believe me or think I'm wrong because I am younger you do you.
Answer:

Explanation:
It is given that,
Mass of the baseball, m = 0.14 kg
It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

h = 1.8 m

u = 5.93 m/s
Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

h' = 1.4 m

v = -5.23 m/s
The change in the momentum of the ball is given by :



So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.