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just olya [345]
3 years ago
14

I am in plato cuzz wauup what u doing

Physics
1 answer:
Irina-Kira [14]3 years ago
8 0
Yoohoo dudio!!! whatz up??!!

MARK AS THE BRAINLIEST SWEETY!!
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Greenhouse gases:___________,
masha68 [24]
Btw the answer is number 4
5 0
3 years ago
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During a baseball game, a batter hits a high pop-up. If the ball remains in the air for 6.82 s, how high does it rise? The accel
scoray [572]
The answer is 56.98 m

The dislocation (d) is:
d = v1 * t + 1/2 * a * t²
v1 - initial velocity
t - time
a - <span>acceleration of gravity

We know:
d = ?
v1 = ?
t = 6.82 s / 2 = 3.41  (it reaches the peak at half time)
a = - 9.8 m/s</span>²

Let's first calculate v1:
v2 = v1 + at
v2 - final velocity (v2 = 0 when it reaches peak)

0 = v1 + -9.8 * 3.41
0 = v1 - 33.418

v1 = 33.418 m/s

d = v1 * t + 1/2 * a * t²
d = 33.418 * 3.41 +  1/2 * -9.8 * 3.41²
d = 113.96 - 56.98
d = 56.98 m
8 0
3 years ago
How are doctors both accurate and precise when preforming surgery or other things?
mr Goodwill [35]

Answer:

learning about the different functions of the body and therefore they have enough practice in order to have a clean and safe operation

Explanation:

4 0
3 years ago
a passing warm front changes air pressure. does a passing warm front increase or decrease air pressure
meriva
Warmer air has molecules more spread out, so I'd say a decrease in air pressure.
7 0
3 years ago
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The body weighing 2 kg moves through the horizontal surface and crosses the path x = 75 cm The coefficient of friction of the bo
Taya2010 [7]

The kinetic energy of the body in definitive position is 4.24 J.

Explanation:

As per the work energy theorem, the work done on any system or object to move it from one position to another is equal to the change in kinetic energy of the object. In this case, the body weighing 2 kg is moved over an horizontal surface for a distance of 75 cm. As there will be frictional force acting on the body while moving over the surface. This frictional force multiplied by the distance the object is moved will give the work done on the body.

Frictional force = Coeffficent of friction × Normal force.

As the weight of the body is 2 kg, the normal force acting on it will be mass multiplied with acceleration due to gravity.

Frictional force = - 0.8×9.8 × 2 =-15.68 N

So the work done will be the product of frictional force with the displacement of 75 cm or 0.75 m.

Work done =  Frictional force × Displacement

Work done = -15.68×0.75 = -11.76 J.

So the work is done by the object.

If the kinetic energy of the body at starting is 16 J, then the kinetic energy of the body at definitive position will be obtained as below.

Work done = change in kinetic energy

-11.76 J = Final kinetic energy-16 J

Final Kinetic energy = - 11.76+16

Final kinetic energy = 4.24 J

Thus, the kinetic energy of the body in definitive position is 4.24 J.

3 0
3 years ago
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