[OU.02H]The first coordinate of the celestial coordinate system is called

Describe how substance move from one state to another

Mekhanik [1.2K]

The temperature rises until the water reaches the next change of state — boiling. As the particles move faster and faster, they begin to break the attractive forces between each otherand move freely as steam — a gas. The process by which a substance moves from the liquid state to the gaseousstate is called boiling.

4 0

4 years ago

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A plane leaves the airport in Galisteo and flies 160 km at 66.0 ∘ east of north; then it changes direction to fly 260 km at 49.0

user100 [1]

<u>The question doesn't have any particular requirement, but we'll compute the displacement of the plane from its initial and final landing point in the pasture </u>

Answer:

$\displaystyle |\vec{r}|=321.464\ km$

$\displaystyle \theta =-19.395^o$

Explanation:

<u>Displacement </u>

The vector displacement $\vec r$ is a measure of the change of position of a moving object. The displacement doesn't depend on the path followed, only on the final and initial positions. Its scalar counterpart, the distance, does measure the total space traveled and considers all the changes in the direction taken by the object. To find the displacement, we must add all the particular displacements by using vectors.

The plane first flies 160 km at 66° east of north. To find the vector expression of this displacement, we must know the angle with respect to the East direction or North of East. Knowing the angle East of North is 66°, the required angle is 90°-66°=34°

The first vector is expressed as

$\displaystyle \vec{r_1}=\left \langle 160^o\ cos34^o, 160\ sin34^o \right \rangle$

$\displaystyle \vec{r_1}=\left \langle 132.646, 89.471 \right \rangle$

The second displacement is 260 km at 49° South of East. This angle is below the horizontal respect to the reference, thus we use -49°.

The second vector is expressed as:

$\displaystyle \vec{r_2}=\left \langle 260\ cos(-49^o), 260\ sin(-49^o)\right \rangle$

$\displaystyle \vec{r_2}=\left \langle 170.575,-196.224\right \rangle$

The total displacement is computed as the vectorial sum of both vectors

$\displaystyle \vec{r}=\vec{r_1}+\vec{r_2}=\left \langle 132.646+170.575\right \rangle+ \left \langle89.471-196.224\right \rangle$

$\displaystyle \vec{r}=\left \langle 303.221,-106.753\right \rangle\ km$

The magnitude of the total displacement is

$\displaystyle |\vec{r}|=\sqrt{303.221^2+(-106,753)^2}$

$\displaystyle |\vec{r}|=321.464\ km$

And the direction is

$\displaystyle tan\ \theta =\frac{-106.753}{303.221}=-0.352$

$\displaystyle \theta =-19.395^o$

6 0

3 years ago

1. What were the 3 basic concepts of government that the English brought with them to North America?

aev [14]

Answer:

1)limited system of government

2)representative system of government

3)individual rights system of government

Explanation:

the 3 basic concepts of government that the English brought with them to North America are listed in the answer

7 0

4 years ago

The velocity of a particle is given by v=20t² - 100t + 50, where v is in meters per second and t is in seconds. Evaluate the vel

allochka39001 [22]

Explanation:

It is given that,

The velocity of a particle is given by :

$v=20t^2-100t+50$

Where

v is in m/s and t is in seconds

Let a is the acceleration of the object at time t. So,

$a=\dfrac{dv}{dt}$

$a=\dfrac{d(20t^2-100t+50)}{dt}$

$a=40t-100$

When a = 0

$40t-100=0$

t = 2.5 s

a is zero at t = 2.5 s. Velocity, $v=20(2.5)^2-100(2.5)+50$

v = -75 m/s

Since, $v=\dfrac{ds}{dt}$ , s is the distance travelled

$s=\int\limits{vdt}$

$s=\int\limits{(20t^2-100t+50)dt}$

$s=\dfrac{20t^3}{3}-50t^2+50t$

At t = 2.5 s, $s=\dfrac{20(2.5)^3}{3}-50(2.5)^2+50(2.5)$

s = −83.34 m

Hence, this is the required solution.

5 0

3 years ago

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A pendulum clock depends on the period of a pendulum to keep correct time. Suppose a pendulum clock is keeping correct time and

Mashutka [201]

Answer:

time period is increased so the clock will become SLOW

Explanation:

As we know that the time period of the simple pendulum is given by the formula

$T = 2\pi\sqrt{\frac{L}{g}}$

here we know that

L = distance of the pendulum bob from the hinge

g = acceleration due to gravity

now here the bob slide down so that the length of the pendulum is being increased

so time period T of the pendulum is also increased

so here the pendulum will take more time to oscillate or to complete one oscillation

so clock will become SLOW

8 0

3 years ago