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Leona [35]
3 years ago
8

An observer on Earth sees rocket 1 leave Earth and travel toward Planet X at 0.3c. The observer on Earth also sees that Planet X

is stationary. An observer on Planet X sees rocket 2 travel toward Earth at 0.4c. What is the speed of rocket 1 according to an observer on rocket 2?
Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

0.625 c

Explanation:

Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.

In the context,

The relative speed of body 2 with respect to body 1 can be expressed as :

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

Speed of rocket 1 with respect to rocket 2 :

$u' = \frac{0.4 c- (-0.3 c)}{1-\frac{(0.4 c)(-0.3 c)}{c^2}}$

$u' = \frac{0.7 c}{1.12}$

u'=0.625 c

Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c

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Answer: 2.4×10^-3 v/m

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Potential difference between plates (v) = 12v

Force on electronic charge (f) = 3.8×10^-16 N

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By substituting the parameters, we have that

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<em>500 sec</em>

<em>8 min 20 sec</em>

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<em>Hi there !</em>

<em />

<em>8 m ................ 1 s </em>

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