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Leona [35]
3 years ago
8

An observer on Earth sees rocket 1 leave Earth and travel toward Planet X at 0.3c. The observer on Earth also sees that Planet X

is stationary. An observer on Planet X sees rocket 2 travel toward Earth at 0.4c. What is the speed of rocket 1 according to an observer on rocket 2?
Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

0.625 c

Explanation:

Relative speed of a body may be defined as the speed of one body with respect to some other or the speed of one body in comparison to the speed of second body.

In the context,

The relative speed of body 2 with respect to body 1 can be expressed as :

$u'=\frac{u-v}{1-\frac{uv}{c^2}}$

Speed of rocket 1 with respect to rocket 2 :

$u' = \frac{0.4 c- (-0.3 c)}{1-\frac{(0.4 c)(-0.3 c)}{c^2}}$

$u' = \frac{0.7 c}{1.12}$

u'=0.625 c

Therefore, the speed of rocket 1 according to an observer on rocket 2 is 0.625 c

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sdas [7]

To solve the problem it is necessary to apply the concepts related to heat flow,

The heat flux can be defined as

\frac{dQ}{dt} = H = \frac{kA\Delta T}{d}

Where,

k = Thermal conductivity

A = Area of cross-sectional area

d = Length of the rod

\Delta T= Temperature difference between the ends of the rod

k =388 W/m.\°C Thermal conductivity of copper rod

A = 3.6 *10^{-4} m Area of cross section of rod

\Delta T=100-0=100\°C Temperature difference  

d=1.3m length of rod

Replacing then,

H = \frac{kA\Delta T}{d}

H = \frac{(388)(3.6 *10^{-4})(100)}{1.3}

H=10.7446J

From the definition of heat flow we know that this is also equivalent

H = \dot{m}*L

Where,

\dot{m} = Mass per second

L = 334J/g Latent heat of fusion of ice

Re-arrange to find \dot{m},

H = \dot{m}*L

\dot{m}=\frac{L}{H}

\dot{m}=\frac{334}{10.7446}

\dot{m} = 31.08g/s

\dot{m}= 0.032g/s

Therefore the mass of ice per second that melts is 0.032g

7 0
3 years ago
Compare and contrast chemical reactions and nuclear reactions in terms of particles involved . Select all the statements that ap
Anna11 [10]

Answer:

. A chemical reaction is the rearranging of atoms to form new substances. E=mc^ aleph

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2 years ago
Atoms with many electron shells will let go of their electrons more easily than those with fewer shells.
Anna007 [38]

True

The more the number of shells will let go of their outer electrons more easily because the effective nuclear charge on the outer (valence) electrons will be lower. This is called 'shielding', the outer electrons will be shielded from the nucleus by the inner electrons.

Hope this Helps

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2 years ago
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Determine the acceleration of a pendulum bob as it passes through an angle of 15 degrees to the right of the equilibrium point.
BigorU [14]

Answer:

Explanation:

Since energy is conserved:

2

mu  

2

 

​

=  

2

mv  

2

 

​

+mgh

⇒u  

2

=v  

2

+2gh

⇒(3)  

2

=v  

2

+2(9.8)(0.5−0.5cos60)

⇒v=2m/s

7 0
3 years ago
Two point charges lie on the x axis. A charge of + 2.30 pC is at the origin, and a charge of − 4.50 pC is at x=−11.0cm.
Radda [10]

r₁ = distance of point A from charge q₁ = 0.13 m

r₂ = distance of point A from charge q₂ = 0.24 m

r₃ = distance of point A from charge q₃ = 0.13 m

Electric field by charge q₁ at A is given as

E₁ = k q₁ /r₁² = (9 x 10⁹) (2.30 x 10⁻¹²)/(0.13)² = 1.225 N/C     towards right

Electric field by charge q₂ at A is given as

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Since the electric field in left direction is smaller, hence the electric field by the third charge must be in left direction

Electric field at A will be zero when

E₁ = E₂ + E₃

1.225 = 0.703 + E₃

E₃ = 0.522 N/C

Electric field by charge "q₃" is given as

E₃ = k q₃ /r₃²

0.522 = (9 x 10⁹) q₃/(0.13)²

q₃ = 0.980 x 10⁻¹² C = 0.980 pC

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