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fiasKO [112]
2 years ago
10

In the experiment, “Rolling Along”, which ball had the greater mass?

Physics
1 answer:
olga2289 [7]2 years ago
4 0

Answer:

b

Explanation:

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The vapor pressure of benzene, C6H6, is 40.1 mmHg at 7.6°C. What is its vapor pressure at 60.6°C? The molar heat of vaporization
ANEK [815]

Answer:

The vapor pressure at 60.6°C is 330.89 mmHg

Explanation:

Applying Clausius Clapeyron Equation

ln(\frac{P_2}{P_1}) = \frac{\delta H}{R}[\frac{1}{T_1}- \frac{1}{T_2}]

Where;

P₂ is the final vapor pressure of benzene = ?

P₁ is the initial vapor pressure of benzene = 40.1 mmHg

T₂ is the final temperature of benzene = 60.6°C = 333.6 K

T₁ is the initial temperature of benzene = 7.6°C = 280.6 K

ΔH is the molar heat of vaporization of benzene = 31.0 kJ/mol

R is gas rate = 8.314 J/mol.k

ln(\frac{P_2}{40.1}) = \frac{31,000}{8.314}[\frac{1}{280.6}- \frac{1}{333.6}]\\\\ln(\frac{P_2}{40.1}) = 3728.65 (0.003564 - 0.002998)\\\\ln(\frac{P_2}{40.1}) = 3728.65  (0.000566)\\\\ln(\frac{P_2}{40.1}) = 2.1104\\\\\frac{P_2}{40.1} = e^{2.1104}\\\\\frac{P_2}{40.1} = 8.2515\\\\P_2 = (40.1*8.2515)mmHg = 330.89 mmHg

Therefore, the vapor pressure at 60.6°C is 330.89 mmHg

6 0
3 years ago
Read 2 more answers
The submarine emits a pulse of sound to detect other objects in the sea. The sped of sound in sea water is 1500m/s. An echo is r
r-ruslan [8.4K]

Answer:

d = 375 m

Explanation:

The speed of sound is constant in any medium, therefore we can use the uniform motion relationships

          v = x / t

          x = v t

In this case it indicates that the time since the sound is emitted and received is t = 0.50 s, in this time the sound traveled a round trip distance

           x = 2d

          2d = v t

          d = v t/2

     

let's calculate

          d = 1500 0.5 / 2

          d = 375 m

3 0
3 years ago
The lowest possible frequency that can form in a musical instrument is called the _____. A fundamental frequency B the harmonic
NeX [460]
Perhaps D. if it is the lowebsr possible frequency then it would most likely be the last. I may not be 100 percent right, but that's just an educated guess.
5 0
3 years ago
A cart being pulled with 30N through a 2 m hallway over two seconds. How does it have the greatest power exerted on it
Lapatulllka [165]

Answer:

Power = 30 [watts]

Explanation:

Initia data:

F = force = 30[N]

d = displacement = 2 [m]

By definition we know that work is equal to the product of force by the distance displaced

Therefore:

W = F * d = 30 * 2

W = 60 [J]

And power is defined as the amount of work done in a given time interval

time = t = 2 [sec]

Power = W / t

Power = 60 / 2

Power = 30 [W]

7 0
3 years ago
2. What is the accelaration of a<br> 4000 kg airplane that has a force<br> of 24,000 N?
Bond [772]

Answer:

c) 6 m/s²

Explanation:

8 0
3 years ago
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