In the experiment, “Rolling Along”, which ball had the greater mass?

A 5 kg pineapple is hanging completely still in mid air on a string and suddenly explodes

11111nata11111 [884]

Answer:

Explanation:

Conservation of momentum

Initial momentum is zero

3(15) + 2(v) = 0

v = - 22.5 m/s

v = 22.5 m/s downward

3 0

3 years ago

A beam of light strikes a sheet of glass at an angle of 56.6° with the normal in air. You observe that red light makes an angle

Yuri [45]

Answer:

(a). Index of refraction are $n_{red}$ = 1.344 & $n_{violet}$ = 1.406

(b). The velocity of red light in the glass $v_{red} =$ 2.23 × $10^{8} \ \frac{m}{s}$

The velocity of violet light in the glass $v_{violet} =$ 2.13 × $10^{8} \ \frac{m}{s}$

Explanation:

We know that

Law of reflection is

$n_1 \sin\theta_{1} = n_2 \sin\theta_{2}$

Here

$\theta_1$ = angle of incidence

$\theta_2$ = angle of refraction

(a). For red light

1 × $\sin 56.6$ = $n_{red}$ × $\sin 38.4$

$n_{red}$ = 1.344

For violet light

1 × $\sin 56.6$ = $n_{violet}$ × $\sin 36.4$

$n_{violet}$ = 1.406

(b). Index of refraction is given by

$n = \frac{c}{v}$

$n_{red}$ = 1.344

$v_{red} = \frac{c}{n_{red} }$

$v_{red} = \frac{3(10^{8} )}{1.344}$

$v_{red} =$ 2.23 × $10^{8} \ \frac{m}{s}$

This is the velocity of red light in the glass.

The velocity of violet light in the glass is given by

$v_{violet} = \frac{3(10^{8} )}{1.406}$

$v_{violet} =$ 2.13 × $10^{8} \ \frac{m}{s}$

This is the velocity of violet light in the glass.

8 0

3 years ago

Which, if any, of the following statements about electric field lines is/are true? A.The electric field is always perpendicular

jonny [76]

The electric field is always perpendicular to the surface outside of a conductor. TRUE

 If an electron were placed on an electric field line, it would move in a direction perpendicular to the field. FALSE, it would move in an anti-parallel direction because its charge is negative 

Electric field lines originate on positive charge and terminate on negative charge. TRUE ; but they can also go to infinity 

It is possible for two electric field lines to cross each other.
 Usually FALSE; though technically possible at special points where field is zero. 

If an electron and a positron were in the presence of a very strong electric field, they would move away from each other.
 TRUE; one is positive, and one is negative. If the field is strong enough, the action of the field will overcome the mutual attraction between them 

It is not possible for the electric field to ever be zero. FALSE: it IS possible, inside a conductor for instance

If a proton were placed on an electric field line, it would move in a direction anti-parallel to the field.
 FALSE: being positive, it would move in the SAME direction as the fieldic

8 0

3 years ago

How do scientist determine the the number of iso types?

mash [69]

If you are talking about Isotopes then I believe it is the amount of atoms that have different amounts of neutrons ,but the same number of protons.

3 0

3 years ago

High priority should be given for the development and use oc hydroelectricity justify with reason

olga2289 [7]

Answer:

because hydroelectricity is generate from water and it is considered as a perpetual resources and produce the large capacity of electricity which helps in the indicator of development

5 0

3 years ago