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3 years ago

I HAVE A PHYSICS TEST, ITS 25 QUESTIONS AND I HAVE ABOUT AN HOUR TO SOLVE IT. PLEASE IF YOU’RE GOOD AT PHYSICS CONTACT ME ASAP

Physics

2 answers:

Katena32 [7]3 years ago

5 0

Answer:

in which Class u studying

PilotLPTM [1.2K]3 years ago

4 0

Answer:

okay send me all question I will try my best.

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what law of motion that states that an object will remain at rest or move in a straight line at a constant speed unless it is ac

prohojiy [21]

That's Newton's 1st law of motion, sometimes called the inertia law.

7 0

3 years ago

Recall that the spring constant is inversely proportional to the number of coils in the spring, or that shorter springs equate t

ruslelena [56]

Answer:

$x_1= 0.0425m$

Explanation:

Using the tension in the spring and the force of the tension can by describe by

T = kx

, T = mg

Therefore:

$m*g = k*x$

With two springs, let, T1 be the tension in each spring, x1 be the extension of each spring. The spring constant of each spring is 2k so:

$T_1 = 2k*x_1$

$2T_1 = m*g=4k x_1$

Solve to x1

$x_1=\frac{m*g}{4k}$

$x_1=\frac{k*x}{4*k}$

$x_1=\frac{x}{4}$

$x_1 = 0.170 / 4$

$x_1= 0.0425m$

7 0

3 years ago

I need help with this

polet [3.4K]

Exothermic because the heat make part of the result

7 0

3 years ago

Displacement vector points due east and has a magnitude of 3.35 km. Displacement vector points due north and has a magnitude of

tekilochka [14]

Answer:

(a) 6.56 km

(b) $59.68^\circ$ north of west

Explanation:

Given:

$\vec{d}_1= 3.35\ km\ east = 3.35\ km\ \hat{i}\\\vec{d}_2= 9.31\ km\ north = 9.31\ km\ \hat{j}\\\vec{d}_3= 6.66\ km\ west = -6.61\ km\ \hat{i}\\\vec{d}_4= 3.65\ km\ south = -3.65\ km\ \hat{j}\\$

Let the resultant displacement vector be $\vec{D}$ .

As the resultant is the vector sum of all the vectors.

$\therefore \vec{D}=\vec{d}_1+\vec{d}_2+\vec{d}_3+\vec{d}_4\\\Rightarrow \vec{D} =(3.35\ km\ \hat{i})+(9.31\ km\ \hat{j})+(-6.61\ km\ \hat{i})+(-3.65\ km\ \hat{j})\\\Rightarrow \vec{D} =-3.31\ km\ \hat{i}+5.66\ km\ \hat{j}\\\textrm{Magnitude of the resultant displacement vector} = \sqrt{(-3.31)^2+(5.66)^2}\ km= 6.56\ km\\$

$\textrm{Angle with the positive west} = \theta = \tan^{-1}(\dfrac{5.66}{3.31})= 59.68^\circ$

7 0

4 years ago

If a resultant vector is 12 m/s and the horizontal component is 9 m/s, what is the value of the vertical component? A. 5.8 m/s B

horrorfan [7]

The vertical component is B) 7.9 m/s

Explanation:

A vector can be resolved into its horizontal and vertical components. The horizontal and the vertical components form the sides of a right triangle, in which the resultant corresponds to the hypothenuse, so we can use Pythagorean's theorem:

$R=\sqrt{R_x^2+R_y^2}$

where

R is the resultant vector

Rx is the horizontal component

Ry is the vertical component

In this problem, we have:

R = 12 m/s is the resultant vector

Rx = 9 m/s is the horizontal component

Solving the formula for Ry, we find the vertical component:

$R_y = \sqrt{R^2-R_x^2}=\sqrt{12^2-9^2}=7.9 m/s$

Learn more about vector components:

brainly.com/question/2678571

#LearnwithBrainly

3 0

3 years ago