Answer:
bro just go to an easier class
Explanation:
#nerd
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:
P = ρgh
This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:
P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
The sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.
<h3>What is the Kichoff's loop rule?</h3>
Kirchhoff's loop rule states that the algebraic sum of potential differences, as well as the voltage supplied by the voltage sources and resistances, in any loop must be equal to zero.
In a series RLCcircuit, the voltages are not added by scalar addition but by vector addition.
Kirchhoff's loop rule is not violated since the voltages across different elements in the circuit are not at their maximum values.
Therefore, the sum of the maximum voltages across each element in a series RLC circuit is usually greater than the maximum applied voltage because voltages are added by vector addition.
Learn more about Kichoff's loop rule at: https://brainly.in/question/35360816
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Answer: The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
Explanation:
Force applied on the golf ball = 
Mass of the ball = 0.05 kg
Velocity with which ball is accelerating = 44 m/s
Time period over which forece applied = t
Newton seconds
The magnitude of impulse imparted to the ball by the golf club is 2.2 N seconds
