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3 years ago

The side lengths of a triangle are 5, 3, and 4. Is this a right triangle?

Mathematics

2 answers:

valkas [14]3 years ago

8 0

Answer:

Step-by-step explanation:

yes it is a right triangle because if you do 5 squared 3 squared 4 squared youll get 16+9=25 so yes

denis23 [38]3 years ago

6 0

Answer:

Yes.

Step-by-step explanation:

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(2x + y)2 – (3x – 2y)2 + (x – 4y)(x + 4y<br>11

Vinvika [58]

Answer:

Step-by-step explanation:

(a+ b)² = a² + b² + 2ab

(2x + y)² = (2x)² + y² + 2*2x *y

= 4x² + y² + 4xy

(a- b)² = a² + b² - 2ab

(3x - 2y)² = (3x)² + (2y)² - 2*3x *2y

= 9x² + 4y² - 12xy

(a - b)(a +b) = a² - b²

(x - 4y(x + 4y) = x² - (4y)²

= x² - 16y²

(2x + y)² - (3x - 2y)² + (x - 4y)(x +4y)

= 4x² + y² + 4xy - (9x² + 4y² - 12xy) + x² - 16y²

= 4x² + y² + 4xy - 9x² - 4y² + 12xy + x² - 16y²

= 4x² - 9x² + x² + y² - 4y² - 16y²+ 4xy + 12xy

= -4x² - 19y² + 16xy

8 0

3 years ago

Gina looked at the architectural plan of a room with four walls in which the walls meet each other at right angles. The length o

Lerok [7]

For a better understanding of the solution provided here, please find the diagram attached.

In the diagram, ABCD is the room.

AC is the diagonal whose length is 18.79 inches.

The length of wall AB is 17 inches.

From the given information, we have to determine the length of the BC, which is depicted a $x$ , because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.

In order to determine the length of the wall BC, or $x$ , we will have to employ the Pythagoras' Theorem here. Thus:

$x=\sqrt{(AC)^2-(AB)^2}$

$x=\sqrt{(18.79)^2-(17)^2}\approx\sqrt{64.06} \approx8$

Thus, $BC\approx 8$ inches

$\therefore AB\neq BC$ and hence, the given room is not a square.

8 0

3 years ago

Please answer this question, 27 points and brainliest!

Sati [7]

Answer:

the coordinates of the center of rotation is (4 , 3)

Step-by-step explanation:

*The line which passes through points (4 , 1) and (4 , 5) is vertical because the points have same x coordinates and its length is 5 - 1 = 4

*The line which passes through points (2 , 3) and (6 , 3) is horizontal because the points have same y coordinates and its length is 6 - 2 = 4

*These two lines intersect each other at their mid-point and this mid-point is the center of rotation

*The mid point is $(\frac{4+4}{2},\frac{5+1}{2} )= (4,3)$

or $(\frac{2+6}{2},\frac{3+3}{2}=(4,3)$

6 0

3 years ago

56k ÷ 2k; k=3 can someone help me out

Jobisdone [24]

The answer is 28
Hope this helped!!

7 0

3 years ago

How do you solve X/2-5=10

Afina-wow [57]

Answer: x2-5=10

Two solutions were found :

x = ± √15 = ± 3.8730

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2" was replaced by "x^2".

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

x^2-5-(10)=0

Step by step solution :

Step 1 :

Trying to factor as a Difference of Squares :

1.1 Factoring: x2-15

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =

A2 - AB + BA - B2 =

A2 - AB + AB - B2 =

A2 - B2

Note : AB = BA is the commutative property of multiplication.

Note : - AB + AB equals zero and is therefore eliminated from the expression.

Check : 15 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step 1 :

x2 - 15 = 0

Step 2 :

Solving a Single Variable Equation :

2.1 Solve : x2-15 = 0

Add 15 to both sides of the equation :

x2 = 15

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:

x = ± √ 15

The equation has two real solutions

These solutions are x = ± √15 = ± 3.8730

Two solutions were found :

x = ± √15 = ± 3.8730

Step-by-step explanation:

5 0

3 years ago